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vladimir2022 [97]
4 years ago
14

Which statement is true about a catalyst?

Chemistry
1 answer:
kicyunya [14]4 years ago
7 0

Answer:

The answer should be A. Hope this helps!

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Will give brainlist need answers asap
Serga [27]

Answer:

40 g

Explanation:

Find the line labeled KClO3 (which might take you a min, theres a lot of lines here)

Notice that when the line creates a direct point, you can measure the exact temperature needed to dissolve a certain amount (like how they gave 30 degrees and it lined up perfectly with the 10 g line. )

Since its asking for the amount at 80 degrees, all you need to do is trace the line to the 80 degree point, and look at the grams. (notice it made a direct point, so there definitely should be any decimals or guesswork)

By reading the graph, you can tell that at 80 degrees, it dissolves 40 grams, and that is your answer.

Hope this helps :)

3 0
3 years ago
The melting point of chromium is 1890. The melting point of argon is -189. Suggest a reason for this difference.
DanielleElmas [232]

Answer:

Different forces between atoms and difference in structure.

4 0
4 years ago
An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume
liberstina [14]

Answer:

M KIO3 = 1.254 mol/L

Explanation:

  • molarity (M) [=] mol/L

∴ w KIO3 = 553 g

∴ mm KIO3 = 214.001 g/mol

∴ volumen sln = 2.10 L

⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol

⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)

⇒ M KIO3 = 1.254 mol/L

3 0
4 years ago
Read 2 more answers
What is the final temperature when 150.0 g of water at 90.0 °c is added to 100.0 g of water at 30.0 OC? Note that C, of water ca
levacccp [35]

Answer : The final temperature is, 337.8K

Explanation :

Q_{absorbed}=Q_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of water at 90^oC = 150 g

m_2 = mass of water at 30^oC= 100 g

T_{final} = final temperature = ?

T_1 = temperature of lead = 90^oC=273+90=363K

T_2 = temperature of water = 30^oC=273+30=303K

c_1\text{ and }c_2 = same (for water)

Now put all the given values in equation (1), we get

150\times (T_{final}-363)=-[100\times (T_{final}-303)]

T_{final}=337.8K

Therefore, the final temperature is, 337.8K

8 0
4 years ago
Read 2 more answers
6CO2 + 6H20 + Energy
nata0808 [166]

Answer:

The correct answer is d. 6H20 + 6CO2 the reactant in the chemical reaction 6H2O + 6CO2 ---> C6H12O6 + 6O2 is 6H20 + 6CO2. Remember that the reactant is always at the left side of the equation. So the correct answer is 6H20 + 6CO2 since it's in the left of the equation. I hope this answer helped you.

7 0
3 years ago
Read 2 more answers
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