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3 years ago

Will give brainlist need answers asap

Chemistry

1 answer:

Serga [27]3 years ago

3 0

Answer:

40 g

Explanation:

Find the line labeled KClO3 (which might take you a min, theres a lot of lines here)

Notice that when the line creates a direct point, you can measure the exact temperature needed to dissolve a certain amount (like how they gave 30 degrees and it lined up perfectly with the 10 g line. )

Since its asking for the amount at 80 degrees, all you need to do is trace the line to the 80 degree point, and look at the grams. (notice it made a direct point, so there definitely should be any decimals or guesswork)

By reading the graph, you can tell that at 80 degrees, it dissolves 40 grams, and that is your answer.

Hope this helps :)

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Which electrolyte is used in an alkali fuel cell?

lyudmila [28]

Answer: an aqueous potassium hydroxide solution

An alkaline fuel cell is a zero-emission device whose one major component is the electrolyte. An electrolyte, on the other hand, is a solution that is able to conduct electricity. In an alkaline fuel cell. The electrolyte is an alkaline liquid, and potassium hydroxide also known as KOH is the only alkaline liquid among the choices.

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3 years ago

Help !!!!!!!!!!!!!!!!!!!

horsena [70]

I hope this helps
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3 years ago

How many milliliters of a 2.00 M KBr are needed to prepare 250.0 mL of 0.60 M KBr?

PIT_PIT [208]

Answer:

75 ml

Explanation:

I did it on a Solution Calculator online.

Heres the link to the calculator to do it yourself if you want:

- https://www.sigmaaldrich.com/chemistry/stockroom-reagents/learning-center/technical-library/solution-dilution-calculator.html

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4 years ago

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How do you think the crocodile might affected if it wandered near a strong magnet?

vodomira [7]

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3 years ago

Calculate ΔHo for the following reaction ussing the given bond dissociation energiesCH4(g) + 2O2(g) --> CO2(g) + 2H2O(g)BOND

Mazyrski [523]

Answer:

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

Explanation:

$CH_4(g) + 2O_2(g)\rightarrow CO_2(g) + 2H_2O(g) ,$ ΔH° = ?

We are given with:

$\Delta H_{O-O}=142 kJ/mol$

$\Delta H_{O=O}=498 kJ/mol$

$\Delta H_{H-O}=459 kJ/mol$

$\Delta H_{C-H}=411 kJ/mol$

$\Delta H_{C-O}=358 kJ/mol$

$\Delta H_{C=O}=799 kJ/mol$

ΔH° =

(Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)

$\Delta H^o=(1 mol\times 4\times \Delta H_{C-H}+2 mol\times 1\times \Delta H_{O=O})-(1 mol\times 2\times \Delta H_{C=O}+2 mol\times 2\times\Delta H_{H-O})$

$\Delta H^o=(1 mol\times 4\times 411 kJ/mol+2 mol\times 1\times 498 kJ/mol)-(1 mol\times 2\times 799 kJ/mol+2 mol\times 2\times 459 kJ/mol)$

$\Delta H^o=-794kJ$

$\Delta H^o>0$ endothermic reaction

$\Delta H^o$ exothermic reaction

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

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4 years ago