All categories

3 years ago

Will give brainlist need answers asap

Chemistry

1 answer:

Serga [27]3 years ago

3 0

Answer:

40 g

Explanation:

Find the line labeled KClO3 (which might take you a min, theres a lot of lines here)

Notice that when the line creates a direct point, you can measure the exact temperature needed to dissolve a certain amount (like how they gave 30 degrees and it lined up perfectly with the 10 g line. )

Since its asking for the amount at 80 degrees, all you need to do is trace the line to the 80 degree point, and look at the grams. (notice it made a direct point, so there definitely should be any decimals or guesswork)

By reading the graph, you can tell that at 80 degrees, it dissolves 40 grams, and that is your answer.

Hope this helps :)

You might be interested in

The reaction of equal molar amounts of benzene, C6H6, and chlorine, Cl2, carried out under special conditions, yields a gas and

WINSTONCH [101]

Answer : The molecular formula of a compound is, $C_6H_5Cl_1$

Solution : Given,

Mass of C = 64.03 g

Mass of H = 4.48 g

Mass of Cl = 31.49 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of Cl = 35.5 g/mole

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{64.03g}{12g/mole}=5.34moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{4.48g}{1g/mole}=4.48moles$

Moles of Cl = $\frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{31.49g}{35.5g/mole}=0.887moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{5.34}{0.887}=6.02\approx 6$

For H = $\frac{4.48}{0.887}=5.05\approx 5$

For Cl = $\frac{0.887}{0.887}=1$

The ratio of C : H : Cl = 6 : 5 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = $C_6H_5Cl_1$

The empirical formula weight = 6(12) + 5(1) + 1(35.5) = 112.5 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{112.5}{112.5}=1$

Molecular formula = $(C_6H_5Cl_1)_n=(C_6H_5Cl_1)_1=C_6H_5Cl_1$

Therefore, the molecular of the compound is, $C_6H_5Cl_1$

5 0

3 years ago

Which of the molecules below must be shown with resonance structures?

timama [110]

It seems that you have missed the given options for this question, but anyway, the correct answer is NONE OF THE ABOVE. None of the molecules given must be shown with resonance structures. A resonance structure is defined as the way or presenting <span>delocalized electrons within certain molecules or polyatomic ions. This bonding cannot be expressed by one single Lewis </span><span>structure. Hope this answer helps.</span>

8 0

4 years ago

It has been proposed that mitochondria and chloroplasts are modern descendants of early prokaryotic cells that began to reside a

slamgirl [31]

Answer:

mitochondria and chloroplasts both have prokaryotic ribososmes

Explanation:

Mitochondria and chloroplasts are the modern descendants of early prokaryotic cells. These lived in primitive cells and later developed into part of them.
This hypothesis is supported because both mitochondria and chloroplasts have their own primitive ribosomes. These two organs contain 70s ribosomes.

8 0

3 years ago

Which term describes this reaction?

castortr0y [4]

Answer:Biopolymer: the monomeric amino acids are linked through an

amide bond (the carboxylic acids of one AA with the α-amino

group of a second)

Explanation:

6 0

3 years ago

Given the concentrations, calculate the equilibrium constant for this reaction: PCl3(g) +Cl2(g)⇌PCl5(g) At equilibrium, the mola

maxonik [38]

Answer: Thus the value of the equilibrium constant is $2.4\times 10^1$

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

At eqm. conc. (0.20) M (0.25) M (1.20) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}$

$K_c=\frac{1.20}{0.20\times 0.25}=24=2.4\times 10^1$

The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Thus the value of the equilibrium constant is $2.4\times 10^1$

5 0

3 years ago