Answer:
73.46839716589713698731965
Explanation:
Determine if all the starting material is converted to the product.
<h3>What is TLC?</h3>
Because it can provide immediate and important information about a sample's purity and whether or not a reaction is still ongoing, TLC is a common technique in the organic chemistry lab. A TLC plate can be finished in less than 5 minutes when low polarity solvents are used.
<h3>Uses of TLC:-</h3>
TLC is a chromatographic method used to separate mixtures that are not volatile.
Thin-layer chromatography can be used to:-
- Assess a substance's purity.
- Identify the compounds present in a particular combination.
- Track the development of a reaction.
Learn more about TLC here:-
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Answer:
pH = 1.32
Explanation:
H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺
This problem involves a weak diprotic acid which we can solve by realizing they amount to buffer solutions. In the first deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:
So first calculate the moles reacted and produced:
n H₂M = 0.864 g/mol x 1 mol/ 116.072 g = 0.074 mol H₂M
54 mL x 1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH
it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.
moles H₂M left = 0.074 - 0.015 = 0.059
moles HM⁻ produced = 0.015
Using the Henderson - Hasselbach equation to solve for pH:
ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325
Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.
For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.