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MatroZZZ [7]
3 years ago
11

Extend the life of your __________ by avoiding fast starts, stops and sharp turns.

Physics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

Tires.

Explanation:

There are the few steps which are discussed below should be taken to increase or extend the life of tires.

(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(2)  Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.

Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.

You might be interested in
If the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide before coming to rest?
Gnoma [55]

Hi there!

We know that:

Ei = Ef

There is work being done on the object, so:

W = Force · displacement = F · d ⇒ work due to friction

KEi - Fd = KEf (0)

KEi = Fd

Input variables:

1/2mv² = μmgd

Cancel out the mass:

1/2v² = μgd

Solve for d:

1/2(5.3²)/(0.05 · 9.81) = 28.63 m

4 0
2 years ago
A solenoid has a length , a radius , and turns. The solenoid has a net resistance . A circular loop with radius is placed around
geniusboy [140]

This question is incomplete, the complete question is;

A solenoid has a length 11.34 cm , a radius 1.85 cm , and 1627 turns. The solenoid has a net resistance of 144.9 Ω . A circular loop with radius of 3.77 cm is placed around the solenoid, such that it lies in a plane whose normal is aligned with the solenoid axis, and the center of the outer loop lies on the solenoid axis. The outer loop has a resistance of 1651.6 Ω. At a time of 0 s , the solenoid is connected to a battery that supplies a potential 34.95 V. At a time 2.58 μs , what current flows through the outer loop?

Answer:

the current flows through the outer loop is 1.3 × 10⁻⁵ A

Explanation:

Given the data in the question;

Length l = 11.34 cm = 0.1134 m

radius a = 1.85 cm = 0.0185 m

turns N = 1627

Net resistance R_{sol = 144.9 Ω

radius b = 3.77 cm = 0.0377 m

R_o = 1651.6 Ω

ε = 34.95 V

t = 2.58 μs = 2.58 × 10⁻⁶ s

Now, Inductance; L = μ₀N²πa² / l

so

L = [ ( 4π × 10⁻⁷ ) × ( 1627 )² × π( 0.0185 )² ] / 0.1134

L = 0.003576665 / 0.1134

L = 0.03154

Now,

ε = d∅/dt = \frac{d}{dt}( BA ) =  \frac{d}{dt}[ (μ₀In)πa² ]

so

ε = μ₀n \frac{dI}{dt}( πa² )

ε = [ μ₀Nπa² / l ] \frac{dI}{dt}

ε = [ μ₀Nπa² / l ] [ (ε/L)e^( -t/R_{sol) ]

I = ε/R_o = [ μ₀Nπa² / R_ol ] [ (ε/L)e^( -t/R_{sol) ]

so we substitute in our values;

I = [ (( 4π × 10⁻⁷ ) × 1627 × π(0.0185)²) / (1651.6 ×0.1134) ] [ ( 34.95 / 0.03154)e^( -2.58 × 10⁻⁶ / 144.9 ) ]

I = [ 2.198319 × 10⁻⁶ / 187.29144 ] [ 1108.116677 × e^( -1.7805 × 10⁻⁸ )

I = [ 1.17374 × 10⁻⁸ ] × [ 1108.116677 × 0.99999998 ]

I = [ 1.17374 × 10⁻⁸ ] × [ 1108.11665 ]

I = 1.3 × 10⁻⁵ A

Therefore, the current flows through the outer loop is 1.3 × 10⁻⁵ A

7 0
3 years ago
Please helpp!! Questions 1-5
Fofino [41]

Answer:

1.

A:Time (minutes)

B: Temp(degrees c)

2. Downward trend (temperature goes down as time goes on )

3.

A: not sure

B: temperature

4.the temperature is going down

5. Closes off any open airways

6 0
3 years ago
What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic
VladimirAG [237]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   v_w  =  2.256 *10^{8} \  m/s

B

  v_e  =  2.21 *10^{8} \  m/s

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  n_w  =  1.33

      The  refractive  index of ethanol is  n_e  =  1.36

       

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       v_w  =  \frac{c}{n_w }

Where  c is the speed of light with value  c =  3.0 *10^{8} \  m/s

       v_w  =  \frac{3.0 *10^{8}}{1.33 }

       v_w  =  2.256 *10^{8} \  m/s

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            v_e  =  \frac{ c}{n_e }

  =>       v_e  =  \frac{3.0 *10^{8}}{1.36 }

=>          v_e  =  2.21 *10^{8} \  m/s

4 0
3 years ago
What happens to the temperature of a substance when it is changing state of matter?
noname [10]
Solid substances have molecules held tightly and close together
Liquid substances have molecules moving loosely
Gaseous molecules are moving completely freely

As moleclues get further apart, i.e. As a substance changes state from solid to liquid to gas, molecules gain kinetic energy and vibrate/move more. This means they gain heat energy (the averge energy a substance has) so the temperature increases

Substances exist in different states at different temperatures and different substances will exist in different states at the same temperature. This is to do with the forces between molecules and how much heat (energy) is required to break them
5 0
3 years ago
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