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MatroZZZ [7]
3 years ago
11

Extend the life of your __________ by avoiding fast starts, stops and sharp turns.

Physics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

Tires.

Explanation:

There are the few steps which are discussed below should be taken to increase or extend the life of tires.

(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(2)  Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.

(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.

Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.

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What does gravity, electricity, and magnesium have in common?
Ghella [55]

Answer:

magnesium (Mg), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table, and the lightest structural metal. Its compounds are widely used in construction and medicine, and magnesium is one of the elements essential to all cellular life.

Explanation:

hope it helps

4 0
2 years ago
The 6 kg block is then released and accelerates to the right, toward the 4 kg block. The surface is rough and the coefficient of
KatRina [158]

Answer:

v =3.41 m/s

Explanation:

given,

mass of block 1 = 6 Kg

mass of another block 2 = 4 Kg

coefficient of friction = 0.3

Assuming 6 Kg block is attached to the spring of spring constant 350 N/m

and distance between the two block is equal to 0.5 m

using formula

U = \dfrac{1}{2}kx^2

U = \dfrac{1}{2}\times 350 \times 0.5^2

   U = 43.75 J

using conservation of energy

 KE = U - f.d

where f is the frictional force acting

\dfrac{1}{2}mv^2 = 43.75- \mu m g d

\dfrac{1}{2}\times 6 \times v^2 = 43.75- 0.3\times 6 \times 9.8 \times 0.5

v= \sqrt{11.643}

       v =3.41 m/s

4 0
3 years ago
When friction occurs, which of the following types of energy is produced?
sukhopar [10]

Answer:

heat energy

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Friction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer.

8 0
2 years ago
Read 2 more answers
A particle whose speed is 50 m/sec moves along the line from A(2,1) to B (9,25)
WINSTONCH [101]

First, calculate for the distance between the given points A and B by using the equation,

<span>                                                D = sqrt ((x2 – x1)2 + (y2 – y1)2)</span>

 

Substitute the known values:

<span>                                                D = sqrt((9 – 2)2 + (25 – 1)2)</span>

<span>                                                D = 25 m</span>

 

I assume the unknown here is the time it would require for the particle to move from point A to B. This can be answered by dividing the calculated distance by the speed given above.

<span>                                                t = (25 m)/ (50 m/s) = 0.5 s</span>

 

<span>Thus, it will take 0.5s for the particle to complete the route. </span>

3 0
3 years ago
A car is moving at 5 m/s. 2 seconds later, it is traveling at 17 m/s. How far did the car go?
vekshin1

Answer:

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Explanation:

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