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Elanso [62]
2 years ago
11

Josh tests an unknown liquid substance using litmus paper. When he compared the used litmus paper to a pH scale, the color match

es with a 3.5 of the scale. What kind of substance did Josh test?
Physics
1 answer:
Hunter-Best [27]2 years ago
8 0

Answer:

acid

Explanation:

because ph below 7 is acid

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Water is flowing from a garden hose. A child places his thumb to cover most of those outlet, causing a thin jet of high speed wa
Oxana [17]

Answer: maximum height= 40.8m

Explanation: shown in the attachment.

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This problem has been solved!See the answerCommunication with submerged submarines via radio waves is difficult because seawater
mash [69]

Answer:

4000 km

Explanation:

as we know velocity of electromagnetic wave is c

c = 3 * 10^8 m/s

frequency  given (f) = 76 Hz

wavelength ?

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c =fλ

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λ =  \frac{3 * 10^8}{76}  ≈4000 km

 so final answer λ = 4000km

8 0
3 years ago
Describe a well-known hypothesis that was discarded because it was found to be untrue.earth-centered model of the universe. the
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6 0
3 years ago
What is required for equilibrium to exist
creativ13 [48]
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8 0
3 years ago
a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the
tatuchka [14]
The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
W=mg = (2.5 kg)(9.81 m/s^2)=24.5 N
the force of the wind F, acting horizontally, with intensity
F=12 N
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
T \cos \alpha -F=0
T \sin \alpha -W=
By dividing the second equation by the first one, we get
\tan \alpha =  \frac{W}{F}= \frac{24.5 N}{12 N}=2.04
From which we find
\alpha = 63.8 ^{\circ}
which is the angle of the rope with respect to the horizontal.

By replacing this value into the first equation, we can also find the tension of the rope:
T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N




7 0
3 years ago
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