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2 years ago

11

Josh tests an unknown liquid substance using litmus paper. When he compared the used litmus paper to a pH scale, the color match

es with a 3.5 of the scale. What kind of substance did Josh test?

1 answer:

Hunter-Best [27]2 years ago

8 0

Answer:

acid

Explanation:

because ph below 7 is acid

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An automobile starter motor has an equivalent resistance of 0.0500Ω and is supplied by a 12.0-V battery with a 0.0100-Ω internal

alexandr1967 [171]

Answer

given,

resistance = 0.05 Ω

internal resistance of battery = 0.01 Ω

electromotive force = 12 V

a) ohm's law

V = IR

and volage

$V = \epsilon - Ir$

now,

$IR = \epsilon - Ir$

$I(R+r) = \epsilon$

$I= \dfrac{\epsilon}{R+r}$

inserting the values

$I= \dfrac{12}{0.05+0.01}$

I = 200 A

b) Voltage

V = I R

V = 200 x 0.05

V = 10 V

c) Power

P = I V

P = 200 x 10 = 2000 W

d) total resistance = 0.05 + 0.09 = 0.14 Ω

$I= \dfrac{\epsilon}{R+r}$

$I= \dfrac{12}{0.14+0.01}$

I = 80 A

V = 80 x 0.05 = 4 V

P = 4 x 80 = 320 W

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3 years ago

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Go and click to the invitation bar and you can find an option written as " search friends " . Then it's easy to find that unknown user if you're pretty fond with his/her username and DP ( display picture ).

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3 years ago

A capacitor is charged to a potential difference of 3 volt it delivers 30% store energy to lamp what is the final potential diff

nexus9112 [7]

Answer:

3.98V

Explanation:

Given

Pontential difference V as 3v

Energy delivered is 30%,

Recall that Enery E=1/2cv^2 from this E=V^2(since Current C is not provided we can assume a value 2)

So E=V^2

E=3^2=9

At full charge E=9,30%of 9,0.3*9=2.7 energy in capacitor is 9-2.7=6.3

But E=V^2

✓E=V

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4 0

3 years ago

During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where i

alukav5142 [94]

Answer:

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

$d=vt+\frac{1}{2}at^2$

Now by substituting values in, we get

$d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2$

d = 19.796m

7 0

3 years ago

Consider a steel cable with a diameter of 8.0 mm. Calculatethe stress in the cable when it holds a person weighing 850 N.Report

pishuonlain [190]

Answer:

stress = 16.9 MPa

Explanation:

The stress in the cable can be calculated as:

$\text{Stress = }\frac{F}{A}$

Where F is the force and A is the area. So, the area can be calculated as:

$A=\pi^{}\cdot r^2$

Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:

$\begin{gathered} A=3.14(4\operatorname{mm})^2 \\ A=50.24\operatorname{mm}^2 \end{gathered}$

Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:

$\text{stress = }\frac{850N}{50.24mm^2}=16.9\text{MPa}$

Therefore, the answer is 16.9 MPa

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1 year ago