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The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
<h3>Change in energy level of the electron</h3>
When photons jump from a higher energy level to a lower level, they emit or radiate energy.
The change in energy level of the electrons is calculated as follows;
ΔE = Eb - Ef
ΔE = -2.68 eV - (-5.74 eV)
ΔE = 3.06 eV
Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
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For velocity vs Time graphs, the displacement of the object from 2 seconds to 6 seconds is 30 m.
<h3>What is displacement?</h3>
The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.
In velocity time graphs, the displacement is the area under the curve of the graph on the x axis.
'
A line starts at (0, 2) and ends at (6, 8) in v-t graph
Displacement is equal to the area of a triangle and a rectangle formed under the line.
Area = 1/2 base x height + length x breadth
Area = 1/2 x 6x 6 + 6x2
Area = 18 +12
Area = 30 m
Thus, the displacement is 30 m.
Learn more about displacement.
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Ok so we know:
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660
Using the equation
With 'u' being the initial velocity we want, we get:
So:
So:
So the original/initial velocity was 16.8666 or 16.87 m/s
Hope this helped
