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Archy [21]
3 years ago
12

A nano-satellite has the shape of a disk of radius 0.80 m and mass 8.50 kg.

Physics
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

Explanation:

moment of inertia of satellite I = 1/2 m R²

m is mass and R is radius of the disc

I = 0.5 x 8.5 x 0.8²

= 2.72 kg m²

angular acceleration α = change in angular velocity / time

α = (14.5 - 0) / 30

α = .48333

Let force of each rocket = F

torque created by one rocket = F x R

= F x .8

Torque created by 4 rockets = 4 x .8 F = 3.2 F

3.2 F = I x α

3.2 F =  2.72 x   .48333

F = 0 .41 N

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3 years ago
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Why are road accidents at high speeds very much worse than road accidents at low speeds?
Triss [41]

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The momentum makes it worse.

Explanation:

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The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands
Ghella [55]

Answer:

Pressure on both feet will be 500N/m^2  

Explanation:

Weight of the person F = 500 N

Area of foot print A=0.5m^2

Area of both the foot A=2\times 0.5=1m^2

We have to find pressure on both the feet

Pressure is equal to ratio of force and area

So pressure P=\frac{F}{A}

P=\frac{500}{1}=500N/m^2

So the pressure on both feet will be 500N/m^2 when person stands on both feet.

7 0
4 years ago
Suppose an automobile has a kinetic energy
enyata [817]

Answer:

Explanation:

Given that,

Kinetic energy of an automobile is 2300J

K.E = 2300J

The formula for kinetic energy is

K.E = ½mv²

So, if the speed of the automobile is increased by 6, what is the kinetic energy

Now v' = 6v.

The mass of the automobile is constant.

Therefore, the kinetic energy is

K.E' = ½mv'²

Where v' = 6v

K.E' = ½m(6v)²

K.E' = ½m × 36v²

K.E' = 36 × ½mv²

Where, from above ½mv² = 2300J

Then,

K.E' = 36 × 2300 = 82,800J

The kinetic energy of the automobile when it increase it's speed is 82,800J

4 0
4 years ago
The speed of light inside a medium is (2.0 x 10^8m/s) What is the index of refraction (n) of the medium?
kondor19780726 [428]

Answer:

Refractive index of a medium = Speed of light in vacuum/Speed of light in a medium

1.5 = 3 x 108 / Speed of light in medium

Speed of light in the medium = 3 x 108 /1.5

= 2 x 108 m/s.

Explanation:

3 0
2 years ago
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