Question

A Jeep accelerated at 2.2 m/s2 until after 18 seconds its displacement was 660 meters. Assuming the Jeep traveled in a straight line, calculate the initial velocity.

Answer 1

Ok so we know:
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660

Using the equation
$r = ut + \frac{1}{2} a {t}^{2}$
With 'u' being the initial velocity we want, we get:
$660 = 18u + 356.4$
So:
$18u = 303.6$
So:
$u = 16.8666$
So the original/initial velocity was 16.8666 or 16.87 m/s

Hope this helped