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bazaltina [42]
2 years ago
9

a football player kicks a ball with a mass of 0.42kg. The average acceleration of the football was 14.8 m/s2. How much force did

the kicker supply to the football
Physics
1 answer:
Zarrin [17]2 years ago
5 0

Answer:

6.216 N

Explanation:

As for Newton's second law of motion

F=ma

where F= the acting force

           m=subjected mass

           a= the acceleration

applying F=ma to the football

F=m*a

 =0.42*14.8

 =6.216 N

6.216 N of a force is supplied to the ball

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Which two of the following involve the same energy transfer. Assume that the same substance and the same mass is involved in all
Elanso [62]
B. evaporation
c. condensation

They are opposite processes that involve the same transfer of energy
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2 years ago
Two samples of dirt are collected from a suspect's tread in his shoe and a crime scene. She notes very similar characteristics.
elena-14-01-66 [18.8K]

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8 0
3 years ago
What is the speed of a wave if it has a wavelength of<br> 42 m and a frequency of 7 hertz?
Nimfa-mama [501]

Answer:

♕ \large{ \red{ \tt{Step - By - Step \: Explanation}}}

☃ \underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} :

  • Frequency ( f ) = 7 Hertz
  • Wavelength ( λ ) = 42m

♨ \underline {\underline{ \orange{ \large{ \tt{T \: O \:  \: F \: I \: N\: D}}}} }:

  • Wave velocity ( v )

☄ \underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}:

✧ \red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}

~Plug the known values and then multiply!

↦ \large{ \tt{7  \times 42}}

↦ \boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}

☥ \large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer :  \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}}

---------------------------------------------------------------

❁ \underline{ \large{  \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \:  \: I\: N \: F \: O}}}} :

  • Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.

  • Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).

  • Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.

# KILL : Excuses

KISS : Opportunities

MARRY : Goals

♪ Hope I helped! ♡

☂ Have a wonderful day / night ! ツ

✎ \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}} ✔

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4 0
3 years ago
A person is riding a motorized tricycle. They weigh 180kg and are moving at 3 m/s over a distance of 300 m. How much work is don
agasfer [191]

If I am to understand this question correctly this is what asks you:

If a person is riding a motorized tricycle how much work do they do?

You may ask yourself, why did I only use part of the question. Simple, the rest is not relevant to what is being asked. The weight, speed, and distance wont affect the person riding any <em><u>motorized vehicle</u></em> other than the time it takes to get from one place to another.

So to answer this question I would say:

Not much, all they really have to do is to steer and set the motorized tricycle to cruise control. Just like any rode certified vehicle.

If you have any questions about my answer please let me know and I will be happy to clarify any misunderstandings. Thanks and have a great day!

3 0
3 years ago
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

4 0
3 years ago
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