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wolverine [178]
3 years ago
12

Which is best supported by the data in the chart?

Physics
1 answer:
bija089 [108]3 years ago
7 0

Answer:

Option C: Current X has a lower potential difference than Current Y.

Explanation:

The chart above only shows the potential difference of difference current.

A careful observation of the chart shows that Current X has a lower potential difference than Current Y.

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A student, standing on a scale in an elevator at rest, sees that his weight is 840 n. as the elevator rises, his weight increase
Firlakuza [10]
<span>1) at rest his weight is 840 N

=> 840N = mass * g => mass = 840 N / g = 840 N / 9.8 m/s^2 = 85.7 kg

2) as the elevator rises, his weight increases to 1050 N,

The reading of the scale is the norma force of it over the body of the person.

And the equation for the force is: Net force = mass * acceleration = normal force - weight at rest

=> mass * acceleration = 1050 N - 840 N = 210 N

acceleration = 210 N / mass = 210 N / 85.7 kg = 2.45 m/s^2 (upward)

3)  when the elevator slows to a stop at the 10th floor, his weight drops to 588 N

=>  mass * acceleration = 588 N - 840 N = - 252 N

=> acceleration = - 252 N / 85.71 kg = - 2.94 m / s^2 (downward)

Answer:

Acceleration at the beginning of the trip 2.45 m/s^2 upward
Acceleration at the end of the trip 2.94 m/s^2 downward
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6 0
3 years ago
Time period of a simple pendulum is measured at Karachi. What change will occur in the time period, if it is measured on mount e
Reil [10]
The period of a pendulum is given by T=2 \pi  \sqrt{ \frac{l}{g} }
since Karachi is near sea level, g is larger than it is on Mt. Everest.  That means the pendulum will have a larger period on Mt. Everest than it would in Karachi.
5 0
3 years ago
In the areas called pauses such as the tropopause, the temperature line is vertical. What does this indicate about the temperatu
ivolga24 [154]

Answer:

the answer is A

Explanation:  The vertical temperature line indicates no change in temperature at those altitudes.

6 0
3 years ago
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In a hydroelectric power plant, 65 m3 /s of water flows from an elevation of 90-m to a turbine-generator, where electricity is g
Mariulka [41]

The electric output of the plant is 48.19 MW

First we need to calculate the water power, it is given by the formula

WP=ρQgh

Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head

Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW

Now the overall efficiency of the hydroelectric power plant is given as

η=\frac{electric power}{water power}

Plugging the values in the above equation

0.84=EP/57.38

EP=48.19 MW

Therefore, the electric output of the plant is 48.19 MW.

3 0
3 years ago
HELP!!!! PLEASE (and there will be more)
Alexus [3.1K]

Answer:

i wanna say tranverse if not surface

Explanation:

6 0
3 years ago
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