the primary functionn of the bias circuit is to hold the circuit stable at the destinated Q-point. true or false

The initial speed of a body is 4.24 m/s. What is its speed after 2.91 s if it accelerates uniformly at -1.76 m/s2

shutvik [7]

Initial velocity=u=4.24m/s
Time=t=2.91s
Acceleration=a=-1.76m/s^2
Final velocity=v

Using 1st equation of kinematics

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=4.24+2.91(-1.76)$

$\\ \sf\longmapsto v=|4.24-5.12|$

$\\ \sf\longmapsto v=0.8m/s$

6 0

3 years ago

When two point charges are a distance dd part, the electric force that each one feels from the other has magnitude F.F . In orde

Harman [31]

Answer:

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. r' = r/2.

Explanation :

The electric force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between charges. It is given by :

$F=\dfrac{kq_1q_2}{r^2}$

r is the separation between charges

$F\propto \dfrac{1}{r^2}$

$r=\sqrt{\dfrac{1}{F}}$

If F'= 2F

$r'=\dfrac{1}{\sqrt{2F} }$

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. $r'=\dfrac{1}{\sqrt{2F} }$ . Hence, this is the required solution.

6 0

3 years ago

A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b

Natasha_Volkova [10]

Answer:

Part a)

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part b)

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

Explanation:

Part a)

By Guass law we know that

$\int E. dA = \frac{q}{\epsilon_0}$

$E. 2\pi rL = \frac{\lambda L}{\epsilon_0}$

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part b)

Outside the outer cylinder we will again use Guass law

$\int E. dA = \frac{q}{\epsilon_0}$

$E. 2\pi rL = \frac{\lambda L}{\epsilon_0}$

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

Part d)

As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different

On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.

4 0

3 years ago

The average mass of a car in the US is 1.440 x 10^6 g. Express this mass in kg.

wolverine [178]

Answer:

Average mass of acar in the US (in kg) = 1440 kg

Explanation:

Average mass of a car in the US (in g) = 1.440 × 10⁶ g

Mass in kg:

$\rm 1 \: g = {10}^{ - 3} \: kg \\ \\ \rm 1.440 \times 10^6 \ g = 1.440 \times 10^6 \times {10}^{ - 3} \ kg \\ \\ \rm = 1.440 \times 10^{6 - 3} \ kg \\ \\ \rm = 1.440 \times 10^3 \ kg \\ \\ \rm = 1.440 \times 1000 \ kg \\ \\ \rm = 1440 \ kg$

5 0

3 years ago

A 4 kg mass is in free fall. What is the velocity of the mass after 11 seconds

Ksju [112]

Velocity of the mass after 11 seconds = ( value of the gravitational acceleration) * ( time )
velocity = ( 9.81 m / s^2 ) ( 11)
velocity = 107.91 meters per second

5 0

3 years ago