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4 years ago

How do ice and water on the ground affect incoming solar radiation?

Chemistry

2 answers:

Rufina [12.5K]4 years ago

8 0

Answer:

Ice and water on the ground affect incoming solar radiation by reflecting 4 percent of solar radiation that reaches the surface. ... When the sun angle is high and water is liquid notice, there is less reflection that takes place.

alexdok [17]4 years ago

4 0

By the chemicals atoms make

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If an element only partially conducts electricity, it would be part of the _______ category. *

dmitriy555 [2]

It would be in the transition metals

5 0

3 years ago

A certain substance X condenses at a temperature of 123.3 degree C . But if a 650. g sample of X is prepared with 24.6 g of urea

Pavel [41]

Answer:

The molal boiling point elevation constant is 1.59 ≈ 1.6 $Kkgmol^{-1}$

Explanation:

To solve this question , we will make use of the equation ,

Δ $T_{b} = i*K_{b} *m$

where ,

Δ $T_{b}$ is the change in boiling point of the substance $X$ ( ° $C$ or $K$ )

$i$ is the Vant Hoff Factor which = 1 in this case ( no unit )

$K_{b}$ is the mola boiling point elevation constant of X ( $Kkgmol^{-1}$ )

$m$ is the molality of the solution which has $(NH_{2})_{2} CO$ as the solute and $X$ as the solution ( $molkg^{-1}$ )

Δ $T_{b}$ = $124.3 -123.3 = 1$ ° $C$ or $K$ ;
$i$ =1;
$m$ = $\frac{moles of solute}{weight of solvent(kg)}$ $molkg^{-1}$

∴ $m = \frac{\frac{24.6}{60} }{\frac{650}{1000} }$

as the weight of $(NH_{2})_{2} CO$ is $60g$ and thus number of moles = $\frac{24.6}{60}$

and the weight of solvent in $kg$ is $\frac{650}{1000}$

4. $K_{b}$ ⇒ ?

∴

$1=1*K_{b} *\frac{\frac{24.6}{60} }{\frac{650}{1000} }$

⇒ $K_{b}$ = $1.59$ ≈ 1.6 $Kkgmol^{-1}$

4 0

3 years ago

One significant difference between gases and liquids is that:

erma4kov [3.2K]

Answer:

Explanation:

all the other answers are wrong or not applicable. hope this helps :)

7 0

3 years ago

What is the energy of a photon that emits a light of frequency 4.47 x 10^14 Hz?

Anarel [89]

Answer:

2.96 x 10^-19 J

Explanation:

I just took the test

6 0

3 years ago

What are the major specials presents in a solution of a strong acid like HCl

lubasha [3.4K]

Answer:

hydrogen ions (H⁺) and chloride ions (Cl⁻)

Explanation:

Hydrochloric acid (HCl) is a strong acid. That means that the compound dissociates completely into ions when is dissolved in water, as follows:

HCl → H⁺ + Cl⁻

The equilibrium is completely shifted to the right side (products). Thus, it is considered that the concentration of the non-dissociated compound (HCl) is negligible, and the major specials present in the solution are the hydrogen ions (H⁺) and chloride ions (Cl⁻).

4 0

3 years ago