The concentration of the HCl solution is 0.72 M.
<h3>How do we calculate the concentration?</h3>
Concentration of the required solution by the use of the known concentration solution will be determine by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of the HCl solution.
- M₂ & V₂ are the molarity and volume of the NaOH solution.
On putting values in the above equation, we get
M₁ = (1)(0.018) / (0.025) = 0.72 M
Hence required concentration of HCl is 0.72M.
To know kore about molarity, visit the below link:
brainly.com/question/24305514
#SPJ1
Answer:
The molarity of urea in this solution is 6.39 M.
Explanation:
Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>; that is
To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.
Our first step is to calculate the moles of urea in 100 grams of the solution,
using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is
60.06 g/mol ÷ 37.2 g = 0.619 mol
Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.
1.032 g/mL ÷ 100 g = 96.9 mL
This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.
0.619 mol/96.9 mL × 1000 mL= 6.39 M
Therefore, the molarity of the solution is 6.39 M.
Answer:
2 Transfer; very different
Explanation:
Ionic compound are compound that are formed from transfer of electron. The cations donate the electron(s) while the anion receive the electron(s). The compound possess a positively charged end and a negatively charge end. Example of ionic compound is NaCl . The sodium donates one electron to the chlorine to fulfill the octet rule. The sodium atom becomes positively charged as it donate electron to the chlorine atom. The chlorine atom becomes negatively charged as it receive electron from Sodium atom.
The atoms that are involve in forming ionic compound have very different electronegativity . Electronegativity is the measure of the ability of an atom to attract a bond pair of electron. For example the NaCl compound, the two atom has verse differences in the electronegativity. Cl atom is far more electronegative than Sodium atom.
The answer is yes I believe so.
