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2 years ago

S + 6 HNO3 → H₂SO4 + 6 NO₂ + 2 H₂O

Chemistry

1 answer:

iris [78.8K]2 years ago

5 0

35 g (Rounded to the nearest tenth) H₂O can be made when 5.8 moles of HNO₃ are consumed.

<h3>What is Mole ratio ?</h3>

Mole Ratio is a conversion factor between compounds in a chemical reaction, that is derived from the coefficients of the compounds in a balanced equation.

The mole ratio is therefore used to convert between quantities of compounds in a chemical reaction.

The mole ratio of HNO₃ and H₂O is 6 : 2

Hence, 16.9 moles of HNO₃ will produce = 2/6 × 5.8 = 1.93 moles of H₂O

Also,

Mass = Moles × M.Mass

Mass = 1.93 mol × 18.02 g/mol

Mass = 34.83 g H₂O

= 35 g (Rounded to the nearest tenth)

Learn more about mole ratio here ;

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Bezzdna [24]

Answer:

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Explanation:

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6 0

3 years ago

Calculate the temperature of 2.0 moles of a gas occupying a volume of 5.0 L at 2.46 atm. (R = 0.08125 L atm/mol L)

Serjik [45]

Answer:

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7 0

3 years ago

Read 2 more answers

A mixture of gases A2 and B2 are introduced to a slender metal cylinder that has one end closed and the other fitted with a pist

REY [17]

Answer:

q < 0, w > 0, the sign of ΔE cannot be determined from the information given

Explanation:

Determination of sign of q

Temperature of the water bath before the reaction = 25 °C

Temperature of the water bath after the completion of the reaction = 28 °C

After the completion of the reaction, temperature of the water bath is increased that means heat is released during the reaction and flows out of the system.

If heat is absorbed by the system, then q is indicated by positive sign and if heat is released by the system, then q is indicated by negative sign.

As in the given case, heat is released by the system, so sign of q is negative, or q < 0

Determination of sign of w

After the completion of the reaction, piston moved downward, that means volume of the system decreases or compression occur. During the compression, work is done on the system.

if work is done on the system, sign of w is positive.

If work is done by the system, sign of w is negative.

In the given case, work is done on the system, therefore sign of w is positive, or w > 0

Determination of sign of ΔE

Relationship between ΔE, q and w is given by first law of thermodynamics:

ΔE = q + w

In this case, q is positive and w is negative, so the sign of ΔE depends of magnitude of q and w. As magnitude of w and q cannot be determined in this case, thus, the given information is insufficient for the determination of sign of ΔE.

So, among the given option, option c is correct.

q < 0, w > 0, the sign of ΔE cannot be determined from the information given

3 0

3 years ago

If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically

Phantasy [73]

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation

NaOH = $\frac{842}{39.9}$

= 21.1 MOLES OF NaOH

Al = $\frac{750}{26.9}$

= 27.8 moles

from the equation

from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

$\frac{1}{3}$ = $\frac{x}{21.1}$

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

= 548.55 grams

theoretical yield from the given data is 548.55 grams

3 0

3 years ago

The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect

DedPeter [7]

Answer: The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect of adding more bromine gas to the reaction chamber?

More fluorine gas will be produced.

More bromine gas will be produced.

More bromine monofluoride gas will be produced.

Less bromine monofluoride gas will be produced.

I think it is more bromine monofluoride will be produce

Explanation:

8 0

2 years ago