Answer:
Reduction: 2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)
Oxidation: H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻
Explanation:
In H₂O₂, hydrogen has the oxidation number +1 and oxygen the oxidation number -1.
In the reduction half-reaction (H₂O₂ is the oxidizing agent), H₂O₂ forms H₂O. The oxidation number of oxygen decreases from -1 to -2.
2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)
In the oxidation half-reduction (H₂O₂ is the reducing agent), H₂O₂ forms O₂. The oxidation number of oxygen increases from -1 to 0.
H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻
Answer:
The reaction occurs and all H2 and O2 unite to form H20
Answer:
A. They are malleable, ductile, and conduct electricity.
Explanation:
<h2>Answer:</h2><h3>Part 1. </h3>
Option B is correct option.
The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing OH- ions.
Explanation:
Full equation:
2MnO2 + H2O + 2e- → Mn2O3 + 2OH-
<h3>Part 2:</h3>
The option B which is Mg is stronger reducing agent than Ag is correct option.
Explanation:
Equation:
Mg(s) + 2Ag+ (aq) → Mg2+ (aq) + 2Ag(s)
According to equation Mg converts to Mg+2 which means it gives to electron to reduce Ag. So it act as an reducing agent.
<h3>Part 3:</h3>
The correct option is B. Which is 5, 1, 8, 5, 1, 4.
Explanation:
Full equation :
5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) --> 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O (l)
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