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Furkat [3]
3 years ago
10

5C + 6O2 = ? What will be the product of molecules formed from this equation?

Chemistry
2 answers:
QveST [7]3 years ago
8 0

Answer:

5C + 6O₂ → 5CO + 7/2 O₂

Explanation:

According to the question the reaction is between carbon and oxygen molecule . The reactant side was given as 5 moles of carbon reacting with 6 moles of oxygen molecules.   The chemical reaction between carbon and excess oxygen will form carbon dioxide but with limited oxygen it will form carbon monoxide.  

Now let us write and balance the actual chemical equation as required from the question. In limited oxygen the reaction will be

The reactant said 5 moles of carbon which is 5 atoms of carbon reacting with 12 atoms of oxygen.  The number of atoms of element on both sides of the chemical equation need to be balance . The balanced equation when oxygen is limited is written as

5C + 6O₂ → 5CO + 7/2 O₂

The product will be 5 moles of carbon monoxide and 3.5 moles of oxygen molecules(7 atoms) since the oxygen is limited . The carbon monoxide later reacts with more oxygen to form carbon dioxide.

harina [27]3 years ago
6 0

Answer:5 moles ofCarbonmonoxide and 3.5 moles of oxygen gas.This in combine to yield carbon dioxide.

Explanation:

5C + 6O2----------5CO + 7/2O2.

When carbon combine with oxygen, carbon monoxide is formed first and it later recombine with oxygen to yield carbon dioxide.

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If a gas in a closed container is pressurized from 15.0 atmospheres to 16.0
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Answer:

T₂ = 317.87 K

Explanation:

Given data:

Initial pressure = 15 atm

Final pressure = 16 atm

Initial temperature = 298 K

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

15 atm / 298K = 16 atm/T₂

T₂ = 16atm × 298 K / 15 atm

T₂ = 4768 atm. K / 15 atm

T₂ = 317.87 K

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