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Furkat [3]
4 years ago
10

5C + 6O2 = ? What will be the product of molecules formed from this equation?

Chemistry
2 answers:
QveST [7]4 years ago
8 0

Answer:

5C + 6O₂ → 5CO + 7/2 O₂

Explanation:

According to the question the reaction is between carbon and oxygen molecule . The reactant side was given as 5 moles of carbon reacting with 6 moles of oxygen molecules.   The chemical reaction between carbon and excess oxygen will form carbon dioxide but with limited oxygen it will form carbon monoxide.  

Now let us write and balance the actual chemical equation as required from the question. In limited oxygen the reaction will be

The reactant said 5 moles of carbon which is 5 atoms of carbon reacting with 12 atoms of oxygen.  The number of atoms of element on both sides of the chemical equation need to be balance . The balanced equation when oxygen is limited is written as

5C + 6O₂ → 5CO + 7/2 O₂

The product will be 5 moles of carbon monoxide and 3.5 moles of oxygen molecules(7 atoms) since the oxygen is limited . The carbon monoxide later reacts with more oxygen to form carbon dioxide.

harina [27]4 years ago
6 0

Answer:5 moles ofCarbonmonoxide and 3.5 moles of oxygen gas.This in combine to yield carbon dioxide.

Explanation:

5C + 6O2----------5CO + 7/2O2.

When carbon combine with oxygen, carbon monoxide is formed first and it later recombine with oxygen to yield carbon dioxide.

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Answer:

Reduction: 2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

Oxidation: H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

Explanation:

In H₂O₂, hydrogen has the oxidation number +1 and oxygen the oxidation number -1.

In the reduction half-reaction (H₂O₂ is the oxidizing agent), H₂O₂ forms H₂O. The oxidation number of oxygen decreases from -1 to -2.

2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

In the oxidation half-reduction (H₂O₂ is the reducing agent), H₂O₂ forms O₂. The oxidation number of oxygen increases  from -1 to 0.

H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

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Read 2 more answers
Chemistry!! Please help asap!! Will mark brainiliest!!
Whitepunk [10]
<h2>Answer:</h2><h3>Part 1. </h3>

Option B is correct option.

The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing  OH- ions.

Explanation:

Full equation:

                                          2MnO2 + H2O + 2e-  → Mn2O3 + 2OH-

<h3>Part 2:</h3>

The option B which is Mg is stronger reducing agent than Ag is correct option.

Explanation:

Equation:

                               Mg(s) + 2Ag+ (aq) → Mg2+ (aq) + 2Ag(s)

According to equation Mg converts to Mg+2 which means it gives to electron to reduce Ag. So it act as an reducing agent.

<h3>Part 3:</h3>

The correct option is B. Which is  5, 1, 8, 5, 1, 4.

Explanation:

Full equation :

                  5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) --> 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O (l)


<h3 />

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