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frozen [14]
3 years ago
7

The electric field strength E 0 is measured at a perpendicular distance R from an infinitely large, thin sheet that contains a u

niform positive charge density σ . In terms of the stated properties and the permittivity of free space ε 0 , write an expression for the electric field strength E at a perpendicular distance 2 R from the sheet.
Physics
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

Electric Field Strength E₀ = E₀ = Constant

Explanation:

The Electric Filed Strength E₀ to an Infinite uniformly charge large sheet is constant how far is it i.e. it is independent of the distance away from the uniformly charge sheet.

Formula: E₀ = σ / 2 ε₀  

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A ______ is a push or pull that one object exerts on another.
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The answer is A. force. 
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A 14.0 gauge copper wire of diameter 1.628 mm carries a current of 12.0 mA . A) What is the potential difference across a 1.80 m
Serga [27]

Answer: a) 139.4 μV; b) 129.6 μV

Explanation: In order to solve this problem we have to use the Ohm law given by:

V=R*I whre R= ρ *L/A  where ρ;L and A are the resistivity, length and cross section of teh wire.

Then we have:

for cooper R=1.71 *10^-8* 1.8/(0.001628)^2= 11.61 * 10^-3Ω

and for silver R= 1.58 *10^-8* 1.8/(0.001628)^2=10.80 * 10^-3Ω

Finalle we calculate the potential difference (V) for both wires:

Vcooper=11.62* 10^-3* 12 * 10^-3=139.410^-6 V

V silver= 10.80 10^-3* 12 * 10^-3=129.6 10^-6 V

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4 years ago
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3 years ago
Projectile Motion—A tennis ball is thrown out a window 28 m above the ground at an initial velocity of 15.0 m/s and 20.0° below
NNADVOKAT [17]

Answer:

The distance will be x = 41.7 [m]

Explanation:

We must first find the components in the x & y axes of the initial velocity.

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The acceleration is the gravity acceleration therefore.

g = 9.81 [m/s^2]

Now we can calculate how long it takes to fall.

y=(v_{o})_{y}*t-0.5*g*t^2\\-28 = 5.13*t-0.5*9.81*t^2\\-28=-4.905*t^2+5.13*t\\4.905*t^2-5.13*t=28\\t = 2.96[s]

With this time we can find the horizontal distance that runs the projectile.

x=(v_{o})_{x}*t\\x=14.09*2.96\\x=41.7[m]

5 0
3 years ago
What is the frequency of a wave that has a wavelength of 0.39 m and a speed
gogolik [260]

Answer:

<h3>The answer is option B</h3>

Explanation:

The frequency of a wave can be found by using the formula

f =  \frac{c}{ \lambda}  \\

where

c is the velocity

From the question

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We have

f =  \frac{86}{0.39}  \\  = 220.512820...

We have the final answer as

<h3>200 Hz</h3>

Hope this helps you

7 0
3 years ago
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