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kumpel [21]
3 years ago
9

What is meant by rusting​

Physics
2 answers:
Aneli [31]3 years ago
8 0

Answer:

<em>The</em><em> </em><em>formation</em><em> </em><em>of</em><em> </em><em>reddish</em><em> </em><em>brown</em><em> </em><em>ferric</em><em> </em><em>oxide</em><em> </em><em>on</em><em> </em><em>iron</em><em> </em><em>by</em><em> </em><em>low</em><em> </em><em>temperature</em><em> </em><em>oxidation</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>presence</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>.</em><em> </em>

<em>make</em><em> </em><em>me</em><em> </em><em>as</em><em> </em><em>brilliant</em><em> </em><em>answer</em><em> </em>

Setler79 [48]3 years ago
3 0

The process of formation of a reddish-brown substance on the surface of the iron objects in the presence of flaky moisture and air is called rusting.

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A ball thrown straight up takes 1.89s to reach a height of 41.6m.
yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

8 0
3 years ago
A golf ball is hit with an initial velocity of 20m/s at an angle of 30° to the horizontal. calculate;
svp [43]

Answer:

tcucugxojfjgfojcigxuogoudyifodtufukdutfuocyjxuogu

3 0
2 years ago
Which is the best explanation of how the Moon formed?
andreev551 [17]
The incorrect answer is C
4 0
3 years ago
Read 2 more answers
A charge of 7.00 mC is placed at opposite corners corner of a square 0.100 m on a side and a charge of -7.00 mC is placed at oth
andrew-mc [135]

Answer:

4.03\times10^{7}N[/tex], 135°

Explanation:

charge, q = 7 mC = 0.007 C

charge, - q = - 7 mC = - 0.007 C

d = 0.1 m

Let the force on charge placed at C due to charge placed at D is FD.

F_{D}=\frac{kq^{2}}{DC^{2}}

F_{D}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1^{2}}=4.41 \times 10^{7}N

The direction of FD is along C to D.

Let the force on charge placed at C due to charge placed at B is FB.

F_{B}=\frac{kq^{2}}{BC^{2}}

F_{B}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1^{2}}=4.41 \times 10^{7}N

The direction of FB is along C to B.

Let the force on charge placed at C due to charge placed at A is FA.

F_{A}=\frac{kq^{2}}{AC^{2}}

F_{D}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1 \times\sqrt{2} \times 0.1 \times\sqrt{2}}=2.205 \times 10^{7}N

The direction of FA is along A to C.

The net force along +X axis

F_{x}=F_{A}Cos45-F_{D}

F_{x}=2.205\times10^{7}Cos45-4.41\times10^{7}=-2.85\times10^{7}N

The net force along +Y axis

F_{y}=F_{B}-F_{A}Sin45

F_{y}=4.41\times10^{7}-2.205\times10^{7}Sin45=2.85\times10^{7}N

The resultant force is given by

F=\sqrt{F_{x}^{2}+F_{y}^{2}}=\sqrt{(-2.85\times10^{7})^{2}+(2.85\times10^{7})^{2}}

F = 4.03\times10^{7}N

The angle from x axis is Ф

tan Ф = - 1

Ф = -45°

Angle from + X axis is 180° - 45° = 135°

5 0
3 years ago
A boy runs at a speed of 3.3 m/s straight off the end of a diving board that is 3 meters above the water. How long is he airborn
svp [43]

Answer:

45

Explanation:

7 0
3 years ago
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