A person travelled 350 m east from his home and returns back home an hour has displacement of_?
1 answer:
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Answer:
a)α= 53.13°
b)The velocity at the highest point = 15 m/s
The acceleration at the highest point = 9.8
c)h=15 m
V=18.02 m/s
Explanation:
Speed of water ,u= 25 m/s
So the horizontal component of speed u = u cos α
Given that horizontal distance cover by water in 3 s is 45 m.
So We know that in projectile motion horizontal acceleration is zero.
In horizontal direction
Distance = Velocity x time
45 = u cos α x 3
u cos α = 45
45 = 25 cos α x 3
cos α = 45/75
α= 53.13°
So the velocity at the highest point = u cos α
The velocity at the highest point = 15 m/s
The acceleration at the highest point = 9.8
Now the velocity along vertical direction(Vo) = u sin α
Vo= 25 sin 53.13°
Vo =20 m/s
h=15 m
So at 15 m above the ground water will strike .
The y-component of velocity after 3 sec
Vy= Vo - g t
Vy = 20 - 10 x 3
Vy= -10 m/s
The horizontal component of velocity will remain 15 m/s.
The resultant velocity
V=18.02 m/s
Answer:
q = 1.815 \times 10^{-8} C
Charge on one plate is positive in nature and on the other plate it is negative in nature.
Explanation:
E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm
According to the Gauss's theorem in electrostatics
The electric field between the two plates
Charge, q = surface charge density x area
q = 1.815 \times 10^{-8} C