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arlik [135]
3 years ago
13

Could someone help with this? Much appreciated!

Chemistry
1 answer:
alekssr [168]3 years ago
6 0

Answer:

The 3rd answer down.

Na²O (sodium oxide) will be a base when exposed to water H²O

Explanation:

Sodium Oxide Na²O, will become Sodium Hydroxide after being exposed to water (at 80% I believe).

The oxygen ion in Na²O has 2 extra electrons which makes it highly charged and very attractive to hydrogen ions. The attraction is so strong that when Na²O comes in contact with H²O, the O(-2) strips off a hydrogen from water, forming 2 x OH ions which of course are still strongly basic.

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Read 2 more answers
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14. A cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a
grin007 [14]

59.78175 kPa is the pressure inside the container when a cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a 4.00 L container at 24.0°C.

<h3>What is an ideal gas equation?</h3>

An ideal gas equation states the relationship between the moles of the substance, temperature, pressure, and volume. The ideal gas equation is given as, PV=nRT

Given data:

P_1=48.0 atm

V_1=3T_1=17.0°C

P_2=?

V_2=4.00 L

T_2=24.0°C

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{48.0 atm X 35.0 mL}{17.0} = \frac{P_2X 4000 ml L}{24.0}

P_2= 0.59 atm = 59.78175 kPa

Hence, 59.78175 kPa is the pressure inside the container when a cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a 4.00 L container at 24.0°C.

Learn more about the  ideal gas equation here:

brainly.com/question/22368165

#SPJ1

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