Answer:
Explanation:
Given that,
Charge density is λ = 12 nC/m
And radius 3cm
r=0.03m.
The charge density of a along a circular arc is given as
λ= Q/πr
Then, Q=πrλ
Q=π×0.03×12×10^-9
Q=1.131×10^-9 C
Q=1.131 nC
Then, electric field along x axis is symmetrical and if cancels out
Now, Ey is in the negative direction
Electric field is given as,
Ey=-2kQ/πr²
K is constant =9×10^9Nm²/C²
Ey=-2×9×10^9×1.131×10^-9/(π ×0.03²)
Ey=7200 N/C.
The direction is negative direction of y axis, check attachment for diagram.
b. Electric potential at the origin is given as
V=Ed
d=r=0.03
V=7200×0.03
V=216V
Well it depends if there negative or positive
A simple harmonic motion is defined by the amplitude and angular frequency of the oscillation, which are represented in the given function as 6 units and 98 rad/s respectively.
<h3>General wave equation for simple harmonic motion</h3>
y = A sinωt
where;
- A is amplitude of the motion
- ω is angular frequency
<h3>Amplitude of the oscillation</h3>
A = 6 units
<h3>Angular frequency of the wave</h3>
ω = 98 rad/s
A simple harmonic motion is defined by the amplitude and angular frequency of the oscillation. Thus, the wave is executing simple harmonic motion.
Learn more about simple harmonic motion here: brainly.com/question/17315536
#SPJ1
Answer:
<em><u>0</u></em><em><u>.</u></em><em><u>9</u></em><em><u>1</u></em>
Explanation:
as equivalence resistance can be found out using the
1/Req = 1/r1 +1/r2 +1/r3......
now, 1/req= 1/2+1/3+1/4
=6/12+4/12+3/12
=13/12
i.e, req =12/13 =0.91
✌️:)
