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dezoksy [38]
3 years ago
13

POINTSSS!!!!!!

Chemistry
1 answer:
Lelu [443]3 years ago
4 0
1 mole CO₂----------- 6.02x10²³ molecules
4 moles  CO₂ ---------- ??

4 x ( 6.02x10²³) / 1 =

= 2.41 x 10²⁴ / 1 => 2.41 x 10²⁴ molecules of CO₂

Answer C
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05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises
OLga [1]

Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

Mass of gold =.?

Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

Note: 1 mL is equivalent to 1 cm³

Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

Therefore, the mass of the gold pebble is 142.82 g

6 0
3 years ago
PLEASE HELP! Class is almost ending, I don't want to repeat.
nikklg [1K]
ANSWERS:

1. 2KClO_{3} ⇒ 2KCl + 3O_{2}

2. H_{2}  C_{2} O_{4}  + 2NaOH ⇒ Na_{2}  C_{2} O_{4}  + 2 H_{2} O

3. 2 C_{10}  H_{22} +  31O_{2} ⇒ 20C O_{2} + 22 H_{2} O

4. 4 H_{2} + Fe_{3} O_{4} ⇒ 3Fe +4 H_{2} O

5. 4P + 5 O_{2} ⇒ 2 P_{2}  O_{5}


I have attached my work for 1-3. I would like to see if you can get 4 and 5 on your own. but, if you are struggling/copnfused please let me know in the comments! :)

6 0
3 years ago
The vapor above a mixture of pentane and hexane at room temperature contains 35.5% pentane by mass. What is the mass percent com
FrozenT [24]
  • The mass percent of Pentane in solution is 16.49%
  • The mass percent of Hexane in solution is 83.51%

<u>Explanation</u>:

  • Take 1 kg basis for the vapor: 35.5 mass% pentane = 355 g pentane with 645 g hexane.
  • Convert these values to mol% using their molecular weights:

Pentane: Mp = 72.15 g/mol -> 355g/72.15 g/mol = 4.92mol

Hexane: Mh = 86.18 g/mol -> 645g/86.18 g/mol = 7.48mol

Pentane mol%: yp = 4.92/(4.92+7.48) = 39.68%

Hexane mol%: yh = 100 - 39.68 = 60.32%

Pp-vap = 425 torr = 0.555atm

Ph-vap = 151 torr = 0.199atm

  • From Raoult's law we know:  

Pp = xp \times Pp - vap = yp \times Pt                                       (1)

Ph = xh \times Ph - vap = yh \times Pt                                       (2)

  • Since it is a binary mixture we can write xh = (1 - xp) and yh = (1 - yp), therefore (2) becomes:

(1 - xp) \times Ph - vap = (1 - yp) \times Pt                                   (3)

  • Substituting (1) into (3) we get:

(1-xp) \times Ph - vap = (1 - yp) \times xp \times Pp - vap / yp            (4)

  • Rearrange for xp:

xp = Ph - vap / (Pp - vap/yp - Pp - vap + Ph - vap)      (5)

  • Subbing in the values we find:

Pentane mol% in solution: xp = 19.08%  

Hexane mol% in solution: xh = 80.92%

  • Now for converting these mol% to mass%, take 1 mol basis for the solution and multiplying it by molar mass:

mp = 0.1908 mol \times 72.15 g/mol

     = 13.766 g

mh = 0.8092 mol \times 86.18 g/mol

     = 69.737 g

  • Mass% of Pentane solution = 13.766/(13.766+69.737)

                                                       = 16.49%

  • Mass% of Hexane solution  = 83.51%
8 0
3 years ago
During the observation / question phase of the scientific method, a scientist is usually: collecting data creating graphs and/or
abruzzese [7]

Answer:

Collecting data  

Step-by-step explanation:

During the observation phase of the scientific method, scientists are collecting data.

They can't create graphs or perform calculations, because they are still collecting data, nor can they report results to a colleague, because they have none to report.

6 0
3 years ago
Read 2 more answers
What happens to the energy when you heat the iron? Why is this happening?
SIZIF [17.4K]

Answer:

When iron is heated in air it reacts with oxygen to form the compound iron oxide. Iron is a solid and oxygen is a gas. 5 Draw diagrams to show how the atoms are arranged in iron, oxygen and iron oxide in the circles below their names. Use different colours for the iron atoms and the oxygen atoms.

Explanation:

3 0
3 years ago
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