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3 years ago

What is the overall reaction order for this rate law: rate = k[A]2[B][C]?

Chemistry

2 answers:

dybincka [34]3 years ago

8 0

Zero order are reactions in which concentration of reactant has NO effect on RATE OF REACTION.

2. First order are reactions in which concentration of one reactant is proportionate to the RATE OF REACTION.

Exp: That means when you increase the concentration of the one reactant, then the rate of reaction will increase by the same degree of extent.

3. Second order are reactions in which concentration of two reactant has an effect on the RATE OF REACTION.

Formula:

1. Zero order Rate = k

2. First order Rate = k(A)^m

3. Second order Rate = k(A)^m(B)^n

where () represents concentration

and equation is mA + nB -> Product.

KonstantinChe [14]3 years ago

5 0

Answer:

The overall reaction order for this rate law is 4.

Explanation:

The order of the reaction is the sum of power of the concentrations of reactants.

$rate=k[x]^a[y]^b$

The order of the reaction = a+b

According to reaction , the rate of the reaction is:

Rate = k[A]2[B][C]

Order of the reaction = 2 + 1 + 1= 4

The overall reaction order for this rate law is 4.

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Now consider the reaction a+2b⇌c for which in the initial mixture qc=[c][a][b]2=387 is the reaction at equilibrium? if not, in w

Paul [167]

Solving this chemistry is a little bit hard because the question didn't give some important detailed.
So first, there are a couple problems with your question.
We will just need to know which direction will it proceed to reach equilibrium.
Your expression for Kc (and Qc ) for the reaction should be:
Kc = [C] / [A] [B]^2
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2 years ago

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3 years ago

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:

element: phosphorus sulfur

co9mposition: 39.185% 60.82%

divide with

atomic mass: 39.185/31.0 g/mol 60.82/32.0g/mol

=1.26mol 1.90mol

smallest mole ratio: 1.26mol/1.26mol =1 1.90mol/1.26 mol =1.50

multiply with 2: 2 3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

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Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

= $P_4S_6$

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2 years ago