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3 years ago

What is the overall reaction order for this rate law: rate = k[A]2[B][C]?

Chemistry

2 answers:

dybincka [34]3 years ago

8 0

Zero order are reactions in which concentration of reactant has NO effect on RATE OF REACTION.

2. First order are reactions in which concentration of one reactant is proportionate to the RATE OF REACTION.

Exp: That means when you increase the concentration of the one reactant, then the rate of reaction will increase by the same degree of extent.

3. Second order are reactions in which concentration of two reactant has an effect on the RATE OF REACTION.

Formula:

1. Zero order Rate = k

2. First order Rate = k(A)^m

3. Second order Rate = k(A)^m(B)^n

where () represents concentration

and equation is mA + nB -> Product.

KonstantinChe [14]3 years ago

5 0

Answer:

The overall reaction order for this rate law is 4.

Explanation:

The order of the reaction is the sum of power of the concentrations of reactants.

$rate=k[x]^a[y]^b$

The order of the reaction = a+b

According to reaction , the rate of the reaction is:

Rate = k[A]2[B][C]

Order of the reaction = 2 + 1 + 1= 4

The overall reaction order for this rate law is 4.

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