Answer:
6
Step-by-step explanation:
fred has 2 peanut butter and 3 jelly
type 1 peanut butter can go with all three types of jelly = 3 pb&js where ther is one constant peanutbutter and 3 different jellys
type 2 peanut butter can go with all three jellies = 3 pb&js where there is one constant peanutbutter and 3 different jellies
3+3=6
there are 6 peanut butter and jelly sandwhiches he could make.
you can also just multiply the numbers (2x3=6)
Answer:
<h2>There is 8% probability of Kitzen winning first and Ava second.</h2>
Step-by-step explanation:
The given table shows that there are 4 students, so there are 4 possible winner in total, but they have different number of tickets.
The total number of tickets is 48, that's the total possible outcomes. Kitzen has a probability of
Ava has a probability of
Now, the probability of having one event and the other is
Therefore, there is 8% probability of Kitzen winning first and Ava second.
(Notice that the probaility is not about Kitzen or Ava winning, it's about winning both, that's why the percentage is low)
Answer:
<h2><em>
B. (b+3c)+(b+3c) </em></h2><h2><em>C. </em><em>
2(b)+2(3c)</em></h2>
Step-by-step explanation:
Given this expression 2(b+3c), its equivalent expression is derived by simply opening up the bracket as shown below;
Open the parenthesis by multiplying the constant outside the bracket with all the variables in parenthesis.
= 2(b+3c)
= 2(b)+ 2(3c)
= 2b +2*3*c
= 2b +6c
It can also be written as sum of b+3c in 2 places i.e (b+3c)+(b+3c) because multiplying the function b+3c by 2 means we are to add the function by itself in two places.
<em>Hence the equivalent expression are (b+3c)+(b+3c) and 2(b)+2(3c) or 2b+6c</em>
A14 adaults 11 kids
Step-by-step explanation:
