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Komok [63]
3 years ago
10

As you are cycling to the Q center one spring day, you pass the construction site at Gant and stop to watch a few minutes. A cra

ne holds bricks on a pallet to an upper floor of the building. Suddenly, a brick falls off the rising pallet. You clock the time it takes to hit the ground at 2.5 s. From how high did the brick fall?
Physics
1 answer:
Rama09 [41]3 years ago
7 0

Answer:

30.63 m

Explanation:

Using y = ut + 1/2gt² where u = initial speed of block = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time of fall = 2.5 s and y = height of fall.

So, substituting the values of the variables into the equation, we have

y = ut + 1/2gt²

y = 0 m/s × 2.5 s + 1/2 × 9.8 m/s² × (2.5 s)²

y = 0 m + 4.9 m/s² × 6.25 s²

y = 0 m + 30.625 m

y = 30.625 m

y ≅ 30.63 m

So, the brick fell 30.63 m

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3 years ago
Given that the concentration of bovine carbonic anhydrase is 3.3 pmol ⋅ L − 1 and R max ( V max ) = 222 μmol ⋅ L − 1 ⋅ s − 1 , d
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Answer:

The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.

Explanation:

Given:

The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1

The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1

The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1

Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1

3 0
3 years ago
Estimate the power you produce in running up a flight of stairs. Give your answer in horsepower (1 hp = 746 W). Suppose you clim
GarryVolchara [31]
The first thing you should do is calculate the work done when climbing the stairs. This work by definition will be given by:
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