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3 years ago

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The steel beams in one part of a building will be 65 feet long. On the blueprint, the architect draws the beams 13 inches long.

For another part of the building, the architect draws 8-inch beams. If the beams are drawn to the same scale, what will be the actual length of the 8-inch beams?

1 answer:

Katarina [22]3 years ago

6 0

Answer:

If the scale is 1 : x, then divide the actual distance by x to calculate the map distance.

Explanation:

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A frictionless spring with a 3-kg mass can be held stretched 0.8 meters beyond its natural length by a force of 40 newtons. If t

Free_Kalibri [48]

Answer:

Explanation:

mass m = 3 kg

spring constant be k

k x .8 = 40 N

k = 40 / .8 = 50 N /m

angular frequency ω = √ ( k / m )

= √ ( 50 / 3 )

= 4.08 rad /s

Let amplitude of oscillation be A .

1/2 k A² = 1/2 m v²

50 A² = 3 x 1²

A = .245 m = 24.5 cm

For displacement , the equation of SHM is

x = A sinωt

= 24.5 sin4.08 t

x = 24.5 sin4.08 t

Here, angle 4.08 t is in radians .

3 0

3 years ago

Atoms in Group 18 elements are inert (chemically unreactive) because ___________________________. A they combined to form molecu

Rom4ik [11]

When you say full valence shell, are you talking about a valence electron shell?

I am learning about atoms and i know a little bit

6 0

3 years ago

Read 2 more answers

What is an asteroid that is pulled off course by a planet’s gravity and orbits around that planet called?

tresset_1 [31]

The definition of the celestial bodies allows us to find that the correct answer for a body that is captured and is in planetary orbit is:

Moon

Asteroids are small rocky bodies that rotate around the Sun, when this body enters the atmosphere of a planet and reaches the surface it is called meteoroids.

A meteorite is a fragment of meteoroid, which has been divided in space or the atmosphere during the entrance to the planet, in general they are smaller

A meteor is the atmospheric phenomenon that occurs when the pattern meteorite or meteoroid enters, that is, it does not correspond to a celestial body.

An asteroid satellite or Moon is a celestial object that revolves captures and around another asteroid, this concept can be extended to an asteroid revolving captures and around a planet

A satellite is a celestial body that orbits a planet, its origin is varied and could be formed during the formation of the planet itself, or by capturing a nearby body during the initial formation of the solar system.

Let's examine the different answers

Moon.

True. A body captured by a planet is generally called the Moon.

Meteoriode.

False. A meteoroid is a body that enters the atmosphere of the plant and reaches its surface.

Meteorite

False. It is a fragment of meteoroid that manages to reach the surface of the planet.

Meteor

False. Atmospheric phenomenon visible when passing a meteoroid or meteorite.

In conclusion, using the definition of celestial bodies we can find that the correct answer for a body that is captured and is in planetary orbit is:

Moon

Learn more here: brainly.com/question/3889451

4 0

3 years ago

Derive the equation of motion of the block of mass m1 in terms of its displacement x. The friction between the block and the sur

Alenkasestr [34]

Answer:

the equivalent mass : $m_e = m_1+m_2+\frac{I}{R^2}$

the equation of the motion of the block of mass $m_1$ in terms of its displacement is = $(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)$

Explanation:

Let use m₁ to represent the mass of the block and m₂ to represent the mass of the cylinder

The radius of the cylinder be = R

The distance between the center of the pulley to center of the block to be = x

Also, the angles of inclinations of the cylinder and the block with respect to the ground to be $\phi$ and $\beta$ respectively.

The velocity of the block to be = v

The equivalent mass of the system = $m_e$

In the terms of the equivalent mass, the kinetic energy of the system can be written as:

$K.E = \frac{1}{2} m_ev^2$ --------------- equation (1)

The angular velocity of the cylinder = $\omega$ : &

The inertia of the cylinder about its center to be = I

The angular velocity of the cylinder can be written as:

$v = \omega R$

$\omega =\frac{v}{R}$

The kinetic energy of the system in terms of individual mass can be written as:

$K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I\omega^2$

By replacing $\omega$ with $\frac{v}{R}$ ; we have:

$K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I(\frac{v}{R})^2$

$K.E = \frac{1}{2}(m_1+ m_2+ \frac{I}{R} )v^2$ ------------------ equation (2)

Equating both equation (1) and (2); we have:

$m_e = m_1+m_2+\frac{I}{R^2}$

Therefore, the equivalent mass : $m_e = m_1+m_2+\frac{I}{R^2}$ which is read as;

The equivalent mass is equal to the mass of the block plus the mass of the cylinder plus the inertia by the square of the radius.

The expression for the force acting on equivalent mass due to the block is as follows:

$f_{block }=m_1gsin \beta$

Also; The expression for the force acting on equivalent mass due to the cylinder is as follows:

$f_{cylinder} = m_2gsin \phi$

Equating the above both equations; we have the equation of motion of the equivalent system to be

$m_e \bar x = f_{cylinder}-f_{block}$

which can be written as follows from the previous derivations

$(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)$

Finally; the equation of the motion of the block of mass $m_1$ in terms of its displacement is = $(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)$

8 0

3 years ago

madreJ [45]

Answer:

$f=6.97\times 10^{14}\ Hz$

Explanation:

Given that,

Wavelength, $\lambda=430\ nm=430\times 10^{-9}\ m$

We need to find the frequency of the violet light.

We know that the relation between frequency and wavelength is given by :

$f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{430\times 10^{-9}}\\\\f=6.97\times 10^{14}\ Hz$

So, the frequency of violet light is $6.97\times 10^{14}\ Hz$ .

7 0

3 years ago