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Ludmilka [50]
3 years ago
7

A 250-mL glass bottle was filled with 242mL of water at 20°C and tightly capped. it was then left outdoor overnight, where the a

verage temperature was -5°C. predict what would happen. the density of water at 20°C is 0.998g/cm^3 and that of ice at -5°C is 0.916g/cm^3.
Chemistry
2 answers:
garri49 [273]3 years ago
3 0
It would freeze. yw btw
Softa [21]3 years ago
3 0

Answer:

The glass bottle will get crack.

Explanation:

Volume of the glass bottles,V = 250 mL

Density of water at 20°C  = 0.998g/cm^3

Mass of water in bottle = M

Volume of water at 20°C ,V' = 250 mL (1cm^3= 1 mL)

V>V'

Density=0.988 g/cm^3=\frac{M}{242 cm^3}

M = 239.096 g

Since mass remains constant, the mass of liquid water will be equal to mass of water when freezes

Density of ice at -5°C = 0.916g/cm^3

Volume of the ice at  -5°C= V''

Density=0.916 g/cm^3=\frac{239.096g}{V'}

V''=261.0218cm^3=261.0218 mL

V''>V>V'

As we can see that volume of water has expanded on freezing and exceeded the volume of the glass bottle. This expansion will result in breaking or cracking of a glass bottle.

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NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
Margarita [4]

Answer:

λ = 0.0167 m = 16.7 mm

Explanation:

The wavelength of these radio waves can be found out by using the formula for the speed of radio waves:

v = fλ

where,

v = speed of radio waves = speed of light = 3 x 10⁸ m/s

f = frequency of radio waves = 18 GHz = 18 x 10⁹ Hz

λ = Wavelength = ?

Therefore,

3 x 10⁸ m/s = (18 x 10⁹ Hz)λ

λ = (3 x 10⁸ m/s)/(18 x 10⁹ Hz)

<u>λ = 0.0167 m = 16.7 mm</u>

4 0
3 years ago
Write the full ionic equation and net ionic equation for sodium dihydrogen phosphate + calcium carbonate, sodium oxilate + calcl
My name is Ann [436]

Answer:

<em>Sodium dihydrogen phosphate + calcium carbonate</em>

<u>Full ionic equation</u>

2 Na⁺(aq) + 2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

<u>Net ionic equation</u>

2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

<em>Sodium oxalate + calcium carbonate</em>

<u>Full ionic equation</u>

2 Na⁺(aq) + C₂O₄²⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + CaC₂O₄(s)

<u>Net ionic equation</u>

C₂O₄²⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + CaC₂O₄(s)

<em>Sodium hydrogen phosphate + calcium carbonate</em>

<u>Full ionic equation</u>

2 Na⁺(aq) + HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + 2 Na⁺(aq) + CO₃²⁻(aq)

<u>Net ionic equation</u>

HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + CO₃²⁻(aq)

Explanation:

Let's consider two kind of equations:

  • Full ionic equation: includes all ions and species that do not dissociate in water.
  • Net ionic equation: includes only ions that participate in the reaction (<em>not spectator ions</em>) and species that do not dissociate in water.
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3 years ago
Match the compounds as organic (O) or inorganic (I).
SashulF [63]
H2O2(I)
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7 0
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hichkok12 [17]

Answer:

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A buffer is defined as the mixture of a weak acid and its conjugate base or vice versa.

For the acetic acid buffer, CH₃CO₂H is the weak acid and its conjugate base is the ion without H⁺, that is CH₃CO₂⁻. The equilibrium equation in water knowing this is:

<h3>CH₃CO₂H + H₂O ⇄ CH₃CO₂⁻ + H₃O⁺</h3>

<em>In the equilibrium, the acid is dissociated in the conjugate base and the hydronium ion.</em>

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Marizza181 [45]

Answer:

1.molecules of atoms

2.chemical bond

3.electrons

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