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tamaranim1 [39]
3 years ago
10

If the half-reaction: Fe3+ + e- = Fe2+ were chosen as the standard reduction potential table reference instead of: 2H+ + 2e- = H

2, what would the Eo value for Zn2+ reduction be?
Chemistry
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

E^{0} for Zn^{2+}\mid Zn system would be -1.53 V

Explanation:

Determination of standard reduction potential of any system is done by placing the system in cathode and a reference half cell in anode and then evaluate the cell potential. The cell potential is the standard reduction potential of the system.

So E_{cell}^{0}=E_{system}^{0}-E_{reference}^{0}

As E_{H^{+}\mid H_{2}}^{0} is equal to 0 therefore cell potential is equal to reduction potential of any system by taking hydrogen electrode as a reference.

E_{Zn^{2+}\mid Zn}^{0} equal to -0.76 V with respect to hydrogen

E_{Fe^{3+}\mid Fe^{2+}}^{0} equal to 0.77 V with respect to hydrogen

Therefore standard reduction potential of Zn^{2+}\mid Zn system when Fe^{3+}\mid Fe^{2+} system is taken as reference is-

E_{cell}^{0}=E_{Zn^{2+}\mid Zn}^{0}-E_{Fe^{3+}\mid Fe^{2+}}^{0}

                          = -0.76 V - 0.77 V

                          = -1.53 V                  

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