Let the weight of soymeal be s, and let the weight of cornmeal be c.
You need a total of 280 lb, so that gives us one equation.
s + c = 280
Now we use the protein to write another equation.
The protein in s lb of soymeal is 0.14s.
The protein in c lb of cornmeal is 0.07c.
The protein in 280 lb of 0.09% protein mix is 0.09(280).
This gives us a second equation.
0.14s + 0.07c = 0.09(280)
Now we solve the two equations as a system of equations.
s + c = 280
0.14s + 0.07c = 0.09(280)
Solve the first equation for s and plug in tot eh second equation.
s = 280 - c
0.14(280 - c) + 0.07c = 25.2
39.2 - 0.14c + 0.07c = 25.2
-0.07c = -14
c = 200
Now we substitute c = 200 in the first equation to find s.
s + 200 = 280
s = 80
Answer: 200 lb of soymeal and 80 lb of cornmeal
Look at the picture.
The common part does not exist.
Answer:
70km per hour is the rate of change
Answer:
this is my answer
Step-by-step explanation:
The expression P(−1.33<z<1.59) represents the area under the standard normal curve above a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded to help find the answer.What is the value of P(−1.33<z<1.59) between the given values oz?Express your answer rounded to 4 decimal places.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Sofia scored 632 on the test.What percent of students scored below Sofia?Round your answer to the nearest hundredth.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Benita scored 432 on the test.What percent of students scored below Benita?Round your answer to the nearest hundredth.The expression P(z<1.00) represents the area under the standard normal curve below a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded so this is going to let you find the answer.
