ANSWER
B.
Explanation : it’s B because the control rods used are usually made of boron which boron is a non fissile material hence won’t undergo fission when bombarded or collided with neutrons.
hibernation exclamation mark
Answer:
5.55 L
Explanation:
This excersise can be solved by the Boyle's law.
This law for gases states that the pressure of a gas in a vessel is inversely proportional to the volume of the vessel.
P₁ . V₁ = P₂ . V₂
The law comes from the Ideal Gases Law, in the first term.
P . V = n . R . T In this case, n . R . T are all constant.
6.35 L . 88.6 kPa = 101.3 kPa . V₂
V₂ = (6.35 L . 88.6 kPa) / 101.3 kPa
V₂ = 5.55 L
It is inversely proportional because, as it happened in this case, pressure was increased, therefore volume decreased.
<u>Answer:</u> The correct answer is Option B.
<u>Explanation:</u>
Decomposition is a type of chemical reaction in which larger compound breaks down into two or more smaller compounds.
Double displacement reactions is defined as the chemical reaction in which exchange of ions takes place.
Synthesis reaction is a type of reaction in which two or more smaller compounds combines to form a single large compound.
Single displacement reaction is a type of reaction in which a more reactive metal displaces a less reactive metal from its chemical reaction.
In stomach, an acid is present known as hydrochloric acid and to neutralize its effect, antacid is taken which has 
as a component.
The reaction between HCl and 
is a type of neutralization reaction and it is a type of double displacement reaction.
The equation between the two follows:
Hence, the correct answer is Option B.
Answer:
1) magnesium chloride
2) b) The copper is getting oxidized from Cu+ to Cu2+ and turns blue.
Explanation:
The work published by David N. Frick, Sukalyani Banik, and Ryan S. Rypma in J Mol Biol. 2007 Jan 26; 365(4): 1017–1032 clearly shows that divalent metal ions of group 2 such as Mg^2+ play an important role in ATP hydrolysis. Addition of EDTA decreased the rate of hydrolysis of ATP (due to sequestration of the divalent ion of group 2) indicating an active participation of divalent ions in the process.
2) The copper I ion is colourless because it is a d^10 specie. However, when it is oxidized to Cu^2+, a blue colour appears in the solution.
