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ICE Princess25 [194]

1 year ago

6

the two stages that take place during distillation are. a.evaporation is folloeed by condensation. b.condensation followed by ev

aporation

1 answer:

ValentinkaMS [17]1 year ago

3 0

Answer:

evapiration followed by condensation

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How are amounts of hydrogen and oxygen gas made from the electrolytic decomposition of water related to the chemical formula of

Len [333]

Very simply, you get twice as much Hydrogen as Oxygen, because the chemical formula is H2O, meaning two hydrogen atoms bonded to one oxygen atom.

4 0

3 years ago

You carefully weigh out 20.00 g of CaCO3 powder and add it to 81.00 g of HCl solution. You notice bubbles as a reaction takes pl

Zepler [3.9K]

Answer:

The relevant equation is:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

Explanation:

1 mol of calcium carbonate can react to 2 moles of Hydrochloric acid to produce 1 mol of water, 1 mol of calcium chloride and 1 mol of carbon dioxide.

The formed CO₂ is the reason why you noticed bubbles as the reaction took place

3 0

2 years ago

What is the molarity of a KF(aq) solution containing 3.0 mol of KF in 2.00L of solution?

sergeinik [125]

Answer : The molarity of $KF$ in the solution is 1.5 M.

Explanation : Given,

Moles of $KF$ = 3.0 mol

Volume of solution = 2.00 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{3.0mol}{2.00L}=1.5mole/L=1.5M$

Therefore, the molarity of $KF$ in the solution is 1.5 M.

4 0

2 years ago

Compounds A, B, and C react according to the following equation. 3A(g) + 2B(g) 2C(g) At 100°C a mixture of these gases at equili

Vedmedyk [2.9K]

Answer:

The value of Kc for the reaction is 3.24

Explanation:

A reversible chemical reaction, indicated by a double arrow, occurs in both directions: reagents transforming into products ( direct reaction) and products transforming back into reagents (inverse reaction)

Chemical Equilibrium is the state in which direct and indirect reactions have the same reaction rate. Then taking into account the rate constant of a direct reaction and its inverse the chemical constant Kc is defined.

Being:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients, the equilibrium constant with the following equation:

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also raised to their stoichiometric coefficients.

Then, in the reaction 3A(g) + 2B(g) ⇔ 2C(g), the constant Kc is:

$Kc=\frac{[C]^{2} }{[A]^{3} *[B]^{2} }$

where:

[A]= 0.855 M
[B]= 1.23 M
[C]= 1.75 M

Replacing:

$Kc=\frac{1.75^{2} }{0.855^{3}*1.23^{2} }$

Solving you get:

Kc=3.24

<u><em>The value of Kc for the reaction is 3.24</em></u>

8 0

2 years ago

Balance the following chemical equation by providing the correct coefficients HBr+Ba(OH)2 ———— BaBr2+H2O

stealth61 [152]

Answer:

2HBr + Ba(OH)2 = BaBr2 + 2H20

4 0

2 years ago