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2 years ago

Which is true of a mechanical wave?

Physics

2 answers:

timurjin [86]2 years ago

5 0

A) It must have a medium.

nydimaria [60]2 years ago

5 0

A) True

Mechanical waves need a medium to travel.

B) False.

Mechanical waves need a medium to travel. So they can not travel in empty space.

C) False

Sound is a mechanical wave since it needs a medium to travel. light wave is electromagnetic wave and it can travel in empty space too.

D) False

Mechanical waves need a medium to travel. So they can not travel in empty space.

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A truck moves 100 miles to the south in 2 hours. What is the trucks velocity

ruslelena [56]

v = d/t

v = 100/2

v=50

50 mph

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3 years ago

Sonar signals and infrared light are are used to send messages to submarines deep under water. If we compare the two signals, wh

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3 years ago

A 2000-kg truck traveling at a speed of 6.0 m/s slows down to 4.0 m/s along a straight road. What

antiseptic1488 [7]

Answer: -4000 kg • m/s

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2 years ago

PLEASE I REALLY NEED HELP!

Talja [164]

Answer:

$v=\dfrac{1200}{t}\ m/s$

Explanation:

Given that,

The car traveled a total of 1,200 meters during this test.

We need to find the average speed of the car. The average speed of the car is given by total distance covered divided by the time taken. So,

$v=\dfrac{1200}{t}\ m/s$

But putting the value of t we can find the average speed of the car.

3 0

3 years ago

The average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km. How much

aleksklad [387]

Answer:

Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

Explanation:

We have been given that the average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km.

We will use Kepler's Law to solve our given problem.

$\frac{(T_1)^2}{(T_2)^2}=\frac{(r_1)^3}{(r_2)^3}$

Upon substituting our given values, we will get:

$\frac{(T_1)^2}{(T_2)^2}=\frac{(238,000)^3}{(1,222,000)^3}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272000000000}{1824793048000000000}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272}{1824793048}$

$\frac{(T_1)^2}{(T_2)^2}=0.0073878361246365$

Taking square root of both sides, we will get:

$\frac{T_1}{T_2}=\sqrt{0.0073878361246365}$

$\frac{T_1}{T_2}=0.0859525225030452495$

$\frac{T_2}{T_1}=\frac{1}{0.0859525225030452495}$

$\frac{T_2}{T_1}=11.634329870476699\approx 11.634$

$T_2=11.634\cdot T_1$

This implies that time period of Titan about Sturn is 11.634 times more compared to time period of Enceladus about Saturn.

So, basically Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

8 0

3 years ago