The distance of the straight wire carrying a current of 15 A is 2.72 mm
<h3 /><h3>What is distance?</h3>
Distance is the length between two points.
To calculate the distance, the straight wire carrying a current of 15 A, we use the formula below.
⇒ Formula:
- r = μ₀i/2πB................. Equation 1
⇒ Where:
- B = Magnetic field
- i = Current
- r = Distance from the straight wire and the magnetic field
- π = pie
- μ₀ = Permeability of free space
From the question,
⇒ Given:
- I = 15 A
- B = 1.1 mT = 1.1×10⁻³ T
- μ₀ = 4π×10⁻⁷ H/m
Substitute these values into equation 1
- r = (4π×10⁻⁷×15)/(2π×1.1×10⁻³)
- r = 2.72×10⁻³ m
- r = 2.72 mm
Hence, the distance of the straight wire carrying a current of 15 A is 2.72 mm
Learn more about distance here: brainly.com/question/2854969
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Loud sound waves have greater __________ and carry more energy than soft ones. *
>><span>amplitude</span>
I believe that the answer to the question provided above is that with increase in resistance provided with constant current, Power dissipated will be lessen since power loss is high. Low power dissipation has low heat production. Hope this helps!! Have a great day!! :)