To determine the amplitude of a transverse wave, measure the highest amount of disturbance from the equilibrium that the wave experiences.
It can be any row
Explanation:
An element with a valence electrons of 3 can be in any row on the periodic table.
The rows are the horizontal arrangement of elements on the periodic table.
Elements on the same row have the same energy level.
- The periodic table rows are called periods.
- It is only in the groups that we can find such element.
- Group 3 elements have 3 valence electrons.
- Since this group cuts through all the rows, therefore, elements with 3 valence electrons can be found in any row.
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Answer:
c. ammonia
Explanation:
Ammonia is a base, so it is most alkaline.
The reaction of acetic acid with sodium hydroxide is:
The ratio of A-/HA is calculated as follows:
According to Henderson Hasslebach equation:
![[A-]/[HA] = 10^p^H^-^p^K^_a](https://tex.z-dn.net/?f=%5BA-%5D%2F%5BHA%5D%20%3D%2010%5Ep%5EH%5E-%5Ep%5EK%5E_a)
The total concentration of HA and A- = 2.0 L * 0.25 M = 0.5 mol.
![[ A- ]+ [ HA ]= 0.5](https://tex.z-dn.net/?f=%5B%20A-%20%5D%2B%20%5B%20HA%20%5D%3D%200.5)
![[ A^- ] = 0.5 – [ HA]](https://tex.z-dn.net/?f=%5B%20A%5E-%20%5D%20%3D%200.5%20%E2%80%93%20%5B%20HA%5D)
[ HA] = 0.156 mol and [ A- ]= 0.343 mol
Total of 0.5 moles of acetic acid is required:
HA = 30.0 g acetic acid
Conversion of 0.343 moles of the acetic acid to acetate can be performed by adding NaOH
= 343 mL
Thus, 343 mL of 1M NaOH is required
