13. How many moles of zinc are in 25.00 g Zn?

At a certain concentration of H2 and NH3, the initial rate of reaction is 0.120 M / s. What would the initial rate of the reacti

mel-nik [20]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

$rate=k[H_2]^2[NH_3]$

At a certain concentration of $H_2 and [tex]I_2, the initial rate of reaction is 0.120 M/s. What would the initial rate of the reaction be if the concentration of [tex]H_2 were halved.Answer : The initial rate of the reaction will be, 0.03 M/sExplanation :Rate law expression for the reaction:[tex]rate=k[H_2]^2[NH_3]$

As we are given that:

Initial rate = 0.120 M/s

Expression for rate law for first observation:

$0.120=k[H_2]^2[NH_3]$ ....(1)

Expression for rate law for second observation:

$R=k(\frac{[H_2]}{2})^2[NH_3]$ ....(2)

Dividing 2 by 1, we get:

$\frac{R}{0.120}=\frac{k(\frac{[H_2]}{2})^2[NH_3]}{k[H_2]^2[NH_3]}$

$\frac{R}{0.120}=\frac{1}{4}$

$R=0.03M/s$

Therefore, the initial rate of the reaction will be, 0.03 M/s

5 0

3 years ago

Is a microwave oven ac or dc

Ronch [10]

Answer:

Microwave Ovens run on AC Input from the power supply.

7 0

3 years ago

Read 2 more answers

I don't understand the question

s344n2d4d5 [400]

How does the picture show that the inner core spins faster than the outer core?

7 0

3 years ago

Read 2 more answers

Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.

Misha Larkins [42]

Avogadro's law states that in a mole of any substance, there are $6.022 \times 10^{23}$ atoms. This means that in the given sample, there are

$\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}$

The atomic mass of sulfur is 32.06 amu.
The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is

$32.06+2(15.9994=64.0588 \text{ g/mol}$

Therefore, the mass is:

$(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}$

7 0

1 year ago

A glass flask whose volume is 1000 cm3 at a temperature of 0.800 C is completely filled with mercury at the same temperature. Wh

ira [324]

Answer: the coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.

Explanation:

Original volume of mercury = 1000 cm3.

The final volume of mercury considering its volume expansion quotient = 1000 + 1000*(1.8*10^-4 *52) = 1000 + 9.36 = 1009.36 cm^3

Considering the glass as a non expanding substance, the complete excess volume of 9.36 cm3 of mercury should have overflown the container, but due to the expansion of glass, the capacity of mercury containment increases and so a lesser amount of mercury flows out.

The amount of mercury that actually flowed out = 8.50 cm3.

So, the expansion of the glass container = 9.36-8.50 = 0.86 cm3.

Using the formula for coefficient of expansion,

coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.

5 0

3 years ago