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Volgvan
3 years ago
9

Storm sewer backup causes your basement to flood at the steady rate of 1 in. of depth per hour. The basement floor area is 2600

ft2. What capacity (gal/min) pump would you rent to (a) keep the water accumulated in your basement at a constant level until the storm sewer is blocked off, and (b) reduce the water accumulation in your basement at a rate of 3 in./hr even while the backup problem exists?

Engineering
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

attached below

Explanation:

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Why was Tetris so popular and use evidence from the text ito support your resp
Softa [21]

Answer:

because it was a cool game at that time

Explanation: u didnt give us any text

pls mark brainliest

4 0
2 years ago
The 150 mm thick wall of a gas fired furnace is constructed of fireclay brick (k=1.5 W/m.K) , tho=2600 kg/m3, and cp=1000 J/kg.K
pashok25 [27]

Answer:

I am thick but I dont know the anwser

8 0
2 years ago
Water flows through a multisection pipe placed horizontally on the ground. The velocity is 3.0 m/s at the entrance and 2.1 m/s a
Alex_Xolod [135]

Answer:

b. 2.3 kPa.

Explanation:

This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:

P_{1} + \rho \cdot \frac{v_{1}^{2}}{2} = P_{2} + \rho \cdot \frac{v_{2}^{2}}{2}

Where:

P_{1}, P_{2} - Pressures at the beginning and at the end of the current line, measured in kilopascals.

\rho - Water density, measured in kilograms per cubic meter.

v_{1}, v_{2} - Fluid velocity at the beginning and at the end of the current line, measured in meters per second.

Now, the pressure difference between these two points is:

P_{1} - P_{2} = \rho \cdot \frac{v_{2}^{2}-v_{1}^{2}}{2}

If \rho = 1000\,\frac{kg}{m^{3}}, v_{1} = 3\,\frac{m}{s} and v_{2} = 2.1\,\frac{m}{s}, then:

P_{1} - P_{2} = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \frac{\left(2.1\,\frac{m}{s} \right)^{2}-\left(3\,\frac{m}{s} \right)^{2}}{2}

P_{1} - P_{2} = -2295\,Pa

P_{1} - P_{2} = -2.295\,kPa (1 kPa is equivalent to 1000 Pa)

Hence, the right answer is B.

7 0
3 years ago
A 24-volt DC battery is connected
butalik [34]
The answer will be : 0 volts.
4 0
1 year ago
The final position of a car can be predicted with the following equation: Position = -2.5 (time) + 25 Where is the car’s positio
nekit [7.7K]

Answer:

The car's position at 3.0 seconds is 17.5 meters. The car will reach 0.0 meters at 10 seconds.

Explanation:

You can rewrite the equation as P= -2.5t+25. t=time and P is equal to position; so you will plug in 3.0 seconds into t. The equation will now look like: P = -2.5(3.0)+25

P = -2.5(3.0) + 25

P = -7.5 + 25

P = 17.5 meters

Now, to find when the car reaches 0.0 meters, we will plug that into P since P = position and will solve for t.

P = -2.5t + 25

0.0 = -2.5t + 25

-25                 -25

-25 = -2.5t

-25/-2.5 = -2.5t/-2.5

10 = t

So the car will reach 0.0 meters at 10 seconds.

8 0
3 years ago
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