1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
In-s [12.5K]
3 years ago
15

What is the purpose of the graphic language?

Engineering
1 answer:
solmaris [256]3 years ago
5 0

Answer:

enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.

You might be interested in
Air enters a well-insulated turbine operating at steady, state with negligible velocity at 4 MPa, 300°C. The air expands to an e
svetoff [14.1K]

Answer:

-3744.45 kW

Explanation:

The energy balance for a turbine is the following:

U_{e}+P_{e}*v_{e}+gz_{e}+\frac{C_{e}^{2}}{2}+q=W+U_{s}+P_{s}*v_{s}+gz_{s}+\frac{C_{s}^{2}}{2}

Where:

U = internal energy, P= pressure, v=volume, g= gravity, z= height, C= velocity, q= heat, W= power.  

Since it is a well-insulated turbine q= 0.

In steady state m (mass flow) is constant.

m=\frac{1}{v_{s}}*A*C

Where v_{s} is the specific volume and A = area.

There is no information about a change in height during the process so we can say that the term (gz) in the equation both in the inlet (e) and outlet (s) is zero.

In the inlet the velocity is negligible so \frac{C_{e}^{2}}{2} is zero.

Also, enthalpy (h) is:

h=U+P*v

Reorganizing the equation with this information we have

h_{e} =W + h_{s} +\frac{C_{s}^{2}}{2}

W= m*(h_{e}- h_{s}-\frac{C_{s}^{2}}{2}) in kW

We can get the enthalpy from thermodynamic tables for the air with the conditions in the inlet and in outlet. These are:

h_{e} (300 C) = 578.81 \frac{kJ}{kg}

h_{s} (100 C) = 273.26 \frac{kJ}{kg}

Mass flow  

The area is the area of the circle A=pi()*r^{2}

A=pi()*(0.3m)^{2}=0.282 m^{2}

We can get the specific volume from thermodynamics tables for air at 100°C. We use this condition because we know the diameter and the velocity in the outlet. This value is  

1.057 \frac{m^{3}}{kg}  

Mass flow is  

m=\frac{1}{1.057\frac{m^{3}}{kg}} * 0.282 m^{2}* 90\frac{m}{s}=24.072 \frac{kg}{s}

So power is:

W= 24.072 \frac{kg}{s}*(578.81 \frac{kJ}{kg}-273.26 \frac{kJ}{kg}+\frac{(90\frac{m}{s})^{2}}{2}=-3744.45 Kw

5 0
4 years ago
What are Teets<br><br> I am so confused right kn
damaskus [11]
A look, a glance, especially a quick or furtive one.
3 0
3 years ago
To reduce the global emission of greenhouse gases, which of the following would be theMOST effective and practical lifestyle cha
Anestetic [448]

Answer:

C. Decrease your consumption of beef.

Explanation:

The production of beef needs lots of land, which leads to trees being cut down, releasing carbon dioxide. Also, the ruminant animals used to produce beef end up farting a lot from their diets, and these farts are of high metane, which leads to greenhouse gases being emitted in the athmosphere.

Common plant proteins, otherwise, produce way less of these gases.

So the correct answer is:

C. Decrease your consumption of beef.

4 0
3 years ago
A rope having a weight per unit length of 0.4 lb/ft is wound 2 1/2 times around a horizontal rod. Knowing that the coefficient o
Mademuasel [1]

Explanation:

Tension in the rope

\begin{aligned}T_{1} &=0.4 \times x \\T_{2} &=100+0.4 \times 10 \\&=104\end{aligned}

M s=0.3  ∅  =2 \cdot 5(2 \pi)=5 \pi

\begin{aligned}\frac{T_{1}}{T_{2}}=e^{\mu \theta} & \Rightarrow \frac{104}{0.4 x}=e^{0.3(5 \pi)} \\& \Rightarrow x=2.34 \mathrm{H}\end{aligned}

NOTE : Refer the image

3 0
3 years ago
Air is drawn from the atmosphere into a turbomachine. At the exit, conditions are 500 kPa (gage) and 130oC. The exit speed is 10
finlep [7]

Answer:

P=- 88.41 KW

Negative sign indicates that power is given to the system.

Explanation:

Given that

P₂=500 KPa

T₂=130°C

V₂=100 m/s

mass flow rate ,m= 0.8 kg/s

Lets take inlet condition for air

T₁=25°C

P₁=100 KPa

V₁=0 m/s

We know that

Heat capacity for air Cp=1.005 KJ/kg.k

We know that for air change in enthalpy only depends only on temperature

Now from first law for open system

h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}+W

1.005\times 298+\dfrac{0^2}{2000}=1.005\times 403+\dfrac{100^2}{2000}+W

W=1.005\times 298-1.005\times 403-\dfrac{100^2}{2000}

W=-110.52 KJ/kg

Shaft power P = m .W

P = -110.52 x 0.8

P=- 88.41 KW

Negative sign indicates that power is given to the system.

 

3 0
4 years ago
Other questions:
  • What is the movement of the piston from top dead center (TDC) to bottom dead center (BDC) called?
    9·1 answer
  • Consider tests of an unswept wing that spans the wind tunnel and whose airfoil section is NACA 23012. Since the wing model spans
    13·1 answer
  • Name four emerging technologies that could significantly impact how the construction industry conducts business.
    12·2 answers
  • Chaplets are used to support a sand core inside a sand mold cavity. The design of the
    13·1 answer
  • A frying pan is connected to a 150-volt circuit. If the resistance of the frying pan is 25 ohms, how many amperes does the fryin
    12·1 answer
  • Which of these parts of a cell phone is least likely to be found on the phone's circult board?
    5·1 answer
  • Define construction document​
    5·1 answer
  • View the picture below and then correctly answer the questions using the following words: Temperate Zone, Tropical Zone, Polar Z
    6·2 answers
  • A detailed image of a brain scan with height, width, and depth is an example of a(n) 3D _________ model.
    15·1 answer
  • What type of diagrams are used to present the conditions that are available to control outputs based on inputs?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!