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3 years ago

What is the purpose of the graphic language?

Engineering

1 answer:

solmaris [256]3 years ago

5 0

Answer:

enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.

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The wall of drying oven is constructed by sandwiching insulation material of thermal conductivity k = 0.05 W/m°K between thin me

masha68 [24]

Answer:

86 mm

Explanation:

From the attached thermal circuit diagram, equation for i-nodes will be

$\frac {T_ \infty, i-T_{i}}{ R^{"}_{cv, i}} + \frac {T_{o}-T_{i}}{ R^{"}_{cd}} + q_{rad} = 0$ Equation 1

Similarly, the equation for outer node “o” will be

$\frac {T_{ i}-T_{o}}{ R^{"}_{cd}} + \frac {T_{\infty, o} -T_{o}}{ R^{"}_{cv, o}} = 0$ Equation 2

The conventive thermal resistance in i-node will be

$R^{"}_{cv, i}= \frac {1}{h_{i}}= \frac {1}{30}= 0.033 m^{2}K/w$ Equation 3

The conventive hermal resistance per unit area is

$R^{"}_{cv, o}= \frac {1}{h_{o}}= \frac {1}{10}= 0.100 m^{2}K/w$ Equation 4

The conductive thermal resistance per unit area is

$R^{"}_{cd}= \frac {L}{K}= \frac {L}{0.05} m^{2}K/w$ Equation 5

Since $q_{rad}$ is given as 100, $T_{o}$ is 40 $T_ \infty$ is 300 $T_{\infty, o}$ is 25

Substituting the values in equations 3,4 and 5 into equations 1 and 2 we obtain

$\frac {300-T_{i}}{0.033} +\frac {40-T_{i}}{L/0.05} +100=0$ Equation 6

$\frac {T_{ i}-40}{L/0.05}+ \frac {25-40}{0.100}=0$

$T_{i}-40= \frac {L}{0.05}*150$

$T_{i}-40=3000L$

$T_{i}=3000L+40$ Equation 7

From equation 6 we can substitute wherever there’s $T_{i}$ with 3000L+40 as seen in equation 7 hence we obtain

$\frac {300- (3000L+40)}{0.033} + \frac {40- (3000L+40)}{L/0.05}+100=0$

The above can be simplified to be

$\frac {260-3000L}{0.033}+ \frac {(-3000L)}{L/0.05}+100=0$

$\frac {260-3000L}{0.033}=50$

-3000L=1.665-260

$L= \frac {-258.33}{-3000}=0.086*10^{-3}m= 86mm$

Therefore, insulation thickness is 86mm

8 0

3 years ago

LEARNING ACTIVITY SHEET

Nady [450]

Answer:

1. It is used to test/check the continuity of the circuit

a. Ohmmeter

2. Is a physical device used to connect electronic test equipment to a device under test

a. Test probes

3. A device inserted to a convenience outlet to conduct electric current

a. Plug

4. Is a stranded wire used to temporary wiring installation and commonly used in extension cord assembly

a. Duplex cord

5. It is a pocket size tool used to test the line wire or circuit if there is a current in it.

a. Test light

6. An instrument used to measure the amount of electrical current intensity in a circuit

b. Ammeter

7. A pocket sized tool used to test the line wire or circuit if there is current in it.

a. Test light

8. A measuring tool used to measure the length of an object in centimeter in it

b) Ruler

9. It is used to measure the diameter of wires/conductors in circular mills. It can measure small and big sizes of wires

a. Micrometer

10. It is used to measure the voltage, resistance and current of a circuit. It is connected in parallel or series with the circuit depending on what to measure

a) Volt-Ohm-milliammeter

11. It is the measuring tool used to measure length, width and thickness of short object and in sketching straight line

Foot rule/ ruler

Explanation:

1. An Ohmmeter tests resistance of a circuit and therefore, indicates if the circuit has continuity (connectivity) by measuring the resistance to the current it sends through the circuit, while the circuit power is switched off

2. A test probe connects a testing equipment to a Device Under Test (DUT)

3. A plug is used to connect an electric appliance to the mains power supply by fitting it into the mains power outlet

4. A duplex cord is used for temporary wiring to supply power in an extension cord assembly

5. A test light is used to determine if a circuit has electric current flowing in it

6. An ammeter measures the amount of direct or alternating current flowing in a circuit

7. Test light is used to check the presence of an electric current in a circuit

8. A ruler is used to measure length and it is marked in cm or in

9. A micrometer measures the diameter of wires placed in between the anvil and spindle

10. A Volt-Ohm-Milliammeter (VOM), is also known as a multimeter that measures voltage, current, and resistance of a circuit

11. A foot rule/ ruler, measures the dimensions of objects that are flat and short

3 0

3 years ago

Yo can someone find me an e-boy?

Vera_Pavlovna [14]

I got a friend how old are you and are you ok dating a bi guy

4 0

4 years ago

13–27. The conveyor belt is moving downward at 4 m>s. If the coefficient of static friction between the conveyor and the 15-k

Feliz [49]

Answer:

See explanation for step by step procedure to get answer.

Explanation:

Given that:

The conveyor belt is moving downward at 4 m>s. If the coefficient of static friction between the conveyor and the 15-kg package B is ms = 0.8, determine the shortest time the belt can stop so that the package does not slide on the belt.

See the attachments for complete steps to get answer.

4 0

3 years ago

One horsepower is the ability to lift 550 pounds a height of one foot in one second or one horsepower is equal to 550ft-lb/s. Ho

madam [21]

Answer:

32 horsepower will be equal to 17600 ft-lb/sec

Explanation:

We have given 1 horsepower = 550 ft-lb/sec

We have to convert 32 horsepower into ft-lb/sec

As we know that 1 horsepower is equal to 550 ft-lb/sec

So for converting horsepower to ft-lb/sec we have multiply with 550

We have given 32 horse power

So $32\ horsepower =32\times 550=17600ft-lb/sec$

So 32 horsepower will be equal to 17600 ft-lb/sec

5 0

4 years ago