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3 years ago

100 points PLEASE HELP!!!

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

4 0

Answer:

C. −0.4, −0.4545454545

Step-by-step explanation:

between −1/2 and −1/3 so it is bet. -0.5 n -0.3333333333333333

only correct ans is C. −0.4, −0.4545454545

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Please help! - Kim needs to place 32 mystery books and 56 biography books on library shelves. She is to place the maximum number

Oksi-84 [34.3K]

A. 8 books on each shelf
B. 4 shelves for mystery, 7 shelves for biography

3 0

3 years ago

Read 2 more answers

Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!

blagie [28]

Question 4

1) $\overline{BD}$ bisects $\angle ABC$ , $\overline{EF} \perp \overline{AB}$ , and $\overline{EG} \perp \overline{BC}$ (given)

2) $\angle FBE \cong \angle GBE$ (an angle bisector splits an angle into two congruent parts)

3) $\angle BFE$ and $\angle BGE$ are right angles (perpendicular lines form right angles)

4) $\triangle BFE$ and $\triangle BGE$ are right triangles (a triangle with a right angle is a right triangle)

5) $\overline{BE} \cong \overline{BE}$ (reflexive property)

6) $\triangle BFE \cong \triangle BGE$ (HA)

Question 5

1) $\angle AXO$ and $\angle BYO$ are right angles, $\angle A \cong \angle B$ , $O$ is the midpoint of $\overline{AB}$ (given)

2) $\triangle AXO$ and $\triangle BYO$ are right triangles (a triangle with a right angle is a right triangle)

3) $\overline{AO} \cong \overline{OB}$ (a midpoint splits a segment into two congruent parts)

4) $\triangle AXO \cong \triangle BYO$ (HA)

5) $\overline{OX} \cong \overline{OY}$ (CPCTC)

Question 6

1) $\angle B$ and $\angle D$ are right angles, $\overline{AC}$ bisects $\angle BAD$ (given)

2) $\overline{AC} \cong \overline{AC}$ (reflexive property)

3) $\angle BAC \cong \angle CAD$ (an angle bisector splits an angle into two congruent parts)

4) $\triangle BAC$ and $\triangle CAD$ are right triangles (a triangle with a right angle is a right triangle)

5) $\triangle BAC \cong \triangle DCA$ (HA)

6) $\angle BCA \cong \angle DCA$ (CPCTC)

7) $\overline{CA}$ bisects $\angle ACD$ (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) $\angle B$ and $\angle C$ are right angles, $\angle 4 \cong \angle 1$ (given)

2) $\triangle BAD$ and $\triangle CAD$ are right triangles (definition of a right triangle)

3) $\angle 1 \cong \angle 3$ (vertical angles are congruent)

4) $\angle 4 \cong \angle 3$ (transitive property of congruence)

5) $\overline{AD} \cong \overline{AD}$ (reflexive property)

6) $\therefore \triangle BAD \cong \triangle CAD$ (HA theorem)

7) $\angle BDA \cong \angle CDA$ (CPCTC)

8) $\therefore \vec{DA}$ bisects $\angle BDC$ (definition of bisector of an angle)

8 0

1 year ago

Item 15

blsea [12.9K]

The right question is that the lowest altitute is 3^8 feet

You are told that the highest altitude is 3 times the lowest altitude =>

highest altitude = 3 * lowest altitude = 3 * 3^8 feet.

Now you use the ruel of mutiplication of powers with the same base: copy the base and sum the exponents => 3 * 3^8 = 3 ^(1+8) = 3^9.

Note: remember that 3 = 3^1.

Answer: 3^9 feet

8 0

3 years ago

Can some please help with this? :)

den301095 [7]

Answer:

Step-by-step explanation:

The stuff that is yellow is the answer!

6 0

3 years ago

How do we find 4and1/4 hours after 11:20pm?

tigry1 [53]

there are 60 minutes in 1 hour, so 1/4 of an hour is 60(1/4), namely 15 minutes.

11:20pm + 4 hours, is 11+4:20, namely 15:20, of course the time system only uses up to 12, so that has to be 3:20, and then we add the 15 minutes.

11+4: 20 + 15.........3:35am.

5 0

3 years ago