A calibration curve requires the preparation of a set of known concentrations of CV, which are usually prepared by dieting a stock solution whose concentration is known.
Answer:
1. Ba2+ 2. Sr2+
Explanation:
When a solution contains the Barium ,Ba²⁺ ion or Strontium, Sr²⁺ ion, they reacts with either H₂SO₄(aq) or Na₂SO₄(aq) to produce a white precipitate of BaSO₄(s) and SrSO₄(s) respectively
The chemical reactions are given below
Ba²⁺ + H₂SO₄(aq) ⇒ BaSO₄(s) + 2H⁺ (aq)
Ba²⁺ + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2Na⁺ (aq)
Sr²⁺ + H₂SO₄(aq) ⇒ SrSO₄(s) + 2H⁺ (aq)
Sr²⁺ + Na₂SO₄(aq) ⇒ SrSO₄(s) + 2Na⁺ (aq)
In a neutral ionic compound, you can determine its sub-scripts by simply flipping the ionic charges and dropping the signs: so AlS would be Al2S3
Answer:

Explanation:
- State of benzene at RTP = liquid
- State of chloroform at RTP = liquid
- Boiling point of benzene = 80.1 °C
- Boiling point of chloroform = 61.2 °C
Since, both of the chemicals are liquids, we can separate it by the process of distillation.
<u>Distillation:</u>
- is the process in which we separate two liquids on the basis of their difference in boiling points.
<u>How it works:</u>
Since chloroform has less boiling point, it will evaporate and collected first and benzene will follow it after sometime.
- Apparatus of distillation is in the attached file.
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