Answer:
smallest unit element are made of
The required volume of water to make the dilute solution of 0.5 M is 188 mL.
<h3>How do we calculate the required volume?</h3>
Required volume of water to dilute the stock solution will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of stock solution.
- M₂ & V₂ are the molarity and volume of dilute solution.
On putting values from the question to the above equation, we get
V₂ = (2)(47) / (0.5) = 188mL
Hence required volume of water is 188 mL.
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The limiting reagent : NH₃
<h3>Further explanation</h3>
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactants become a limiting reactant
Reaction
4NH₃(g)+5O₂(g)⇒4NO(g)+6H₂O(g)
mol NH₃ :
mol O₂ :
mol ratio
NH₃ :
O₂ :
Limiting reactants : NH₃ (smaller ratio)
Answer:
56.97kJ
Explanation:
1 mole of N2 reacts with 73.8kJ
0.772 mole of N2 reacts with xkJ
cross multiply
x= 0.772×73.8
=56.97kJ
