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Paul [167]
3 years ago
12

The chemical equation represents a reaction between ammonia and oxygen to form nitrogen monoxide and water. 4 N H 3 ( g ) + 5 O

2 ( g ) → 4 NO ( g ) + 6 H 2 O ( g ) What is the limiting reagent when a 4.50 g sample of ammonia is mixed with 15.80 g of oxygen?
Chemistry
1 answer:
Vilka [71]3 years ago
3 0

The limiting reagent : NH₃

<h3>Further explanation</h3>

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactants become a limiting reactant

Reaction

4NH₃(g)+5O₂(g)⇒4NO(g)+6H₂O(g)

mol NH₃ :

\tt \dfrac{4.5}{17}=0.265

mol O₂ :

\tt \dfrac{15.8}{32}=0.494

mol ratio

NH₃ :

\tt \dfrac{0.265}{4}=0.06625

O₂ :

\tt \dfrac{0.494}{5}=0.0988

Limiting reactants : NH₃ (smaller ratio)

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A chemist is studying the following reaction: NO + NO2 ⇌ N2O3. She places a mixture of NO and NO2 in a sealed container and meas
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Help Pls!
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Answer:

d= 50.23 g/cm³

Explanation:

Given data:

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density = ?

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