Answer:
Aromatization leads to evolution of carbon dioxide
Explanation:
In p-hydroxybenzoic acid, -OH and -COOH groups remain in para position.
The directing effect of -OH and -COOH group act synergistically to react with three equivalent of bromine.
In para position of -OH group, -COOH remains attached along with a Br atom in a same carbon atom. During aromatization of benzene group, this -COOH group decomposes to give carbon dioxide.
Reaction scheme has been shown below.
Answer:
530.835 g
Explanation:
First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:
- 244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid
Theoretically,<em> one mol of ethyl benzene would produce one mol of benzoic acid</em>. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.
With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:
- 2.00 moles benzoic acid * = 5.00 moles ethyl benzene
Finally we <u>convert moles of ethyl benzene </u>(C₈H₁₀)<u> into grams</u>, using its <em>molar mass</em>:
- 5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene
A chemical reaction occurs when reactant particles collide with proper energy and proper orientation.
Hope this helps! Have a great day! <3
Atomic mass Nickel ( Ni) = 58.69 a.m.u
1 mole ------------- 58.69 g
2.63 moles -------- ??
2.63 x 58.69 / 1 => 154.3547 g
1 g ------------- 1000 mg
154.3547 g ---- ??
154.3547 x 1000 / 1
=> 154,354.7 mg
Answer:
34,6g of (NH₄)₂SO₄
Explanation:
The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:
ΔT = kb×m
Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.
For the problem:
ΔT = 109,7°C-108,3°C = 1,4°C
kb = 1.07 °C kg/mol
Solving:
m = 1,31 mol/kg
As mass of X = 600g = 0,600kg:
1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:
0,785 moles of ions× = 0,262 moles of (NH₄)₂SO₄
As molar mass of (NH₄)₂SO₄ is 132,14g/mol:
0,262 moles of (NH₄)₂SO₄× = <em>34,6g of (NH₄)₂SO₄</em>
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I hope it helps!