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Tems11 [23]
2 years ago
7

You have 47.0 mL of a 2.00 M concentrated or "stock" solution that must be diluted to 0.500 M. How much water should you add?

Chemistry
1 answer:
Inessa [10]2 years ago
6 0

The required volume of water to make the dilute solution of 0.5 M is 188 mL.

<h3>How do we calculate the required volume?</h3>

Required volume of water to dilute the stock solution will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

  • M₁ & V₁ are the molarity and volume of stock solution.
  • M₂ & V₂ are the molarity and volume of dilute solution.

On putting values from the question to the above equation, we get

V₂ = (2)(47) / (0.5) = 188mL

Hence required volume of water is 188 mL.

To know more about volume & concentration, visit the below link:
brainly.com/question/7208546

#SPJ1

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3 0
3 years ago
A train travels at a speed of 30 miles per hour. If 1 mile = 1.6 kilometers, how fast is the train traveling in kilometers per m
Alina [70]
The answer 
 the speed of <span>the train traveling in kilometers per minute can be found by using the following method:
v = </span><span>30 miles per hour
</span><span>1 mile = 1.6 kilometers

just do the calculus by changing miles to kilometers
 </span>1 mile = 1.6 kilometers, so 30 miles= 1.6 km x 30 = 48 km
 so the speed of the train is
v=30 miles / hour = 48km / h = 48km / 60 mn  = 0.8 km/ mn
the answer is
<span>C- 0.8 km/min</span> 
7 0
3 years ago
The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

l = path length

I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

c = 1 mg /mL = {1mg /mL}{\text{Molar mass of myoglobin}}

c = \frac{1 mg/mL}{ 17800 g/mol} = 5.6179\times 10^{-5} mol/L

1 mg = 0.001 g, 1 mL = 0.001 L

A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

A=0.8426 \approx 0.84

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

5 0
3 years ago
Hydrogen peroxide can decompose to water and oxygen by the following reaction
mestny [16]
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As you know decomposition of 2moles now has prodused <span>196kj
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I'm sure it will help.
6 0
3 years ago
Write a balanced chemical equation for the reaction of solid cesium with liquid water.
Alborosie

The balanced equation for reaction of solid cesium with liquid water

= 2Cs + 2H2O → 2CsOH + H2

cesium react with liquid water to produce cesium hydroxide and hydrogen gas

that is 2 moles of Cs react 2 moles of H2O to form 2 moles CsOH and 1 of hydrogen gas

4 0
3 years ago
Read 2 more answers
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