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Ivahew [28]
3 years ago
12

What is the correct balanced equation for the reaction that occurs when aqueous ammonium chloride reacts with aqueous barium nit

rate to produce solid barium chloride and aqueous ammonium nitrate?
Chemistry
1 answer:
Setler [38]3 years ago
5 0

Answer:

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

Explanation:

In balancing a chemical equation we make sure the number of atoms of each element on the reactant side of the equation equals that on the product side

NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + NH_{4}NO_{3}

The equation above represents an unbalanced equation of the reaction of aqueous ammonium chloride  with aqueous barium nitrate .we can balance this equation by adding the right coefficients to reactants and product.

2NH_{4}Cl + Ba(NO_{3} )_{2} ⇒  BaCl_{2} + 2NH_{4}NO_{3}

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A solution of an acid could have a pH of __*<br> 3 to 5<br> 6 to 8<br> 9 to 11<br> 12 to 14
sdas [7]

Answer:

3 to 5

Explanation:

The pH scale is from 0 to 14.

Acids have a pH of anything less than 7.

Anything with a pH greater than 7 is considered to be a base.

If a solution has a pH of 7, it is neutral.

3 to 5 is in the range of less than 7, so a solution of an acid can have this pH.

6 to 8 includes less than 7 , 7 and greater than 7, so it is not just in the range of an acid.

9 to 11 and 12 to 14 are both in the range of greater than 7, so they have to be bases.

Therefore, the correct answer is 3 to 5.

4 0
3 years ago
Which of the following is true about the third shell?
AlladinOne [14]

Answer:

It has 3 subshells, it has 9 orbitals, and it has the capacity for 18 electrons

Explanation:

4 0
3 years ago
Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h
Gwar [14]

<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

7 0
3 years ago
The following reaction has been reported in the chemical literature and gives a single organic product in high yield. Write the
Alla [95]

Answer:

Explanation:

The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.

In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.

The reaction and the structure of the product is as shown in the attachment.

8 0
3 years ago
How many moles of H2 and N2 can be formed by the decomposition of 0.145 mol of ammonia, NH3 ?​
zepelin [54]

Answer:

Explanation:

The moles of H2 and N2 are as follows respectively, 0.3915mol of H2 and 0.1305 mol of N2.

5 0
2 years ago
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