The first answer; Nickel has an atomic number of 28 (28 protons). and cobalt has an atomic number of 27 (27 protons).
Answer:
C) In[reactant] vs. time
Explanation:
For a first order reaction the integrated rate law equation is:

where A(0) = initial concentration of the reactant
A = concentration after time 't'
k = rate constant
Taking ln on both sides gives:
![ln[A] = ln[A]_{0}-kt](https://tex.z-dn.net/?f=ln%5BA%5D%20%3D%20ln%5BA%5D_%7B0%7D-kt)
Therefore a plot of ln[A] vs t should give a straight line with a slope = -k
Hence, ln[reactant] vs time should be plotted for a first order reaction.
<u>Answer:</u> The value of
for the given reaction is 0.224
<u>Explanation:</u>
For the given chemical equation:

The expression of
for given equation follows:
![K_c=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
We are given:
![[HI]_{eq}=0.85M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.85M)
![[H_2]_{eq}=0.27M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D0.27M)
![[I_2]_{eq}=0.60M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.60M)
Putting values in above expression, we get:

Hence, the value of
for the given reaction is 0.224
Answer:
b. glass and charcoal
Explanation:
Step 1: Given data
- Density of Glass: 2.6 g/mL
- Density of charcoal: 0.57 g/mL
- Density of platinum: 21.4 g/mL
Step 2: Determine which material will float in molten lead
Density is an intrinsic property of matter. Less dense materials float in more dense materials. The materials whose density is lower than that of lead and will therefore float on it are glass and charcoal.
Answer:
Yes
Explanation:
Standard temperature and pressure conditions are defined as 1 atm pressure and 273.15 K. On the other hand, standard ambient temperature and pressure conditions are defined as 1 atm pressure and 298.15 K.
Notice, however, that the only change between them is in temperature.
In any standard conditions, the standard atmospheric pressure is equal to 1 atm.
At sea level, the atmospheric pressure is also equal to 1 atm.
Therefore, we may conclude that the standard atmospheric pressure is equivalent to the normal air pressure at sea level. With an increase in altitude, however, the atmospheric pressure decreases.