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tester [92]
3 years ago
10

I need help on these questions on separating ions in solution. The questions are in the photo.

Chemistry
1 answer:
max2010maxim [7]3 years ago
8 0

Answer:

This involves complex calculations

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Explanation:

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3 years ago
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The main reasons why h2co has a higher vapor pressure at a given temperature when compared to ch3oh is that h2co
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You know that each carbon atom can take as much as 4 bonds with other elements. A hydrogen can only take one bond, while an oxygen can take 2. Thus, the chemical formula of H₂CO may be written as H₂C=O which is acetaldehyde. Acetaldehyde is an aldehyde. It has a higher vapor pressure because aldehydes have much stronger bonds than hydrogen bonds in alcohols. Hence, it would need a lot energy, thus higher vapor pressure, to break the bonds of an aldehyde than it would for an alcohol.
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3 years ago
Choose the elements whose atoms you expect to have greater shielding effects?
vovangra [49]

Answer:

  1. be or mg

Explanation:

because of the it is easier to remove electron from the outer most shell

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3 years ago
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Given the initial rate data for the reaction being A + B + C --> D determine the rate expression for the reaction and the (k)
Vesnalui [34]

Answer:

k = 100 mol⁻² L² s⁻¹, r= k[A][B]²

Explanation:

A + B + C --> D

[A] [B] [C] IRR

0.20 0.10 0.40 .20

0.40 0.20 0.20 1.60

0.20 0.10 0.20 .20

0.20 0.20 0.20 .80

Comparing the third and fourth reaction, the concentrations of A and C are constant. Doubling the concentration of B causes a change in the rate of the reaction by a factor of 4.

This means the rate of reaction is second order with respect to B.

Comparing reactions 2 and 3, the concentrations of B and C are constant. Halving the concentration of A causes a change in the rate of the reaction by a factor of 2.

This means the rate of reaction is first order with respect to A.

Comparing reactions 1 and 3, the concentrations of A and B are constant. Halving the concentration of A causes no change in the rate of the reaction.

This means the rate of reaction is zero order with respect to C.

The rate expression for this reaction is given as;

r = k [A]¹[B]²[C]⁰

r= k[A][B]²

In order to obtain the value of the rate constant, let's work with the first reaction.

r = 0.20

[A] = 0.20 [B] = 0.10

k = r / [A][B]²

k = 0.20 / (0.20)(0.10)²

k = 100 mol⁻² L² s⁻¹

8 0
3 years ago
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