I need help on these questions on separating ions in solution. The questions are in the photo.
1 answer:
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Answer:
Velocity = 4.41×10⁵ m/s
Explanation:
The force of attraction between the nucleus and the electron is equal to the centrifugal force acting on the outermost electron due to circular rotation. It can be mathematically written as:
Where,
K is the Coulomb's constant having value 9×10⁹ N. m²/C²
q is the charge on the electron or the proton which is 1.6×10⁻¹⁹ C
r is the radius of the atom
m is the mass of the electron having value 9.1×10⁻³¹ Kg
v is the velocity of the electron.
The equation can be written to calculate the velocity as:
Given that:
r = 1.3×10⁻⁹ m
So,
<u>Velocity = 4.41×10⁵ m/s</u>
Answer:
a.
The molarity of Co³⁺ is 0.027 M
The molarity of Cl⁻ 0.081 M
b.
The molarity of Ni³⁺ is 0.022 M
The molarity of SO₄²⁻ is 0.033 M
c.
The molarity of Na⁺ is 0.031 M
The molarity of MnO₄⁻ is 0.031 M
d.
The molarity of Fe²⁺ is 0.021 M
The molarity of Br⁻ is 0.042 M
Explanation:
The molarity of each ion is the molarity of the salt times the number of ions in the formula. First, we will calculate the molarity of each salt.
<em>a. Cobalt(III) chloride . CoCl₃</em>
The molar mass of CoCl₃ is 165.29 g/mol. The molarity of CoCl₃ is:
The molarity of Co³⁺ is 1 × 0.027 M = 0.027 M
The molarity of Cl⁻ is 3 × 0.027 M = 0.081 M
<em>b. Nickel(III) sulfate . Ni₂(SO₄)₃</em>
The molar mass of Ni₂(SO₄)₃ is 405.57 g/mol. The molarity of Ni₂(SO₄)₃ is:
The molarity of Ni³⁺ is 2 × 0.011 M = 0.022 M
The molarity of SO₄²⁻ is 3 × 0.011 M = 0.033 M
<em>c. Sodium permanganate . NaMnO₄</em>
The molar mass of NaMnO₄ is 141.92 g/mol. The molarity of NaMnO₄ is:
The molarity of Na⁺ is 1 × 0.031 M = 0.031 M
The molarity of MnO₄⁻ is 1 × 0.031 M = 0.031 M
<em>d. Iron(II) bromide. FeBr₂</em>
The molar mass of FeBr₂ is 215.65 g/mol. The molarity of FeBr₂ is:
The molarity of Fe²⁺ is 1 × 0.021 M = 0.021 M
The molarity of Br⁻ is 2 × 0.021 M = 0.042 M