Answer:
Part 1) The area of the figure is 
Part 2) The perimeter of the figure is 
Step-by-step explanation:
Part 1) Find the area of the figure
we know that
The area of the figure is equal to the area of three squares
so
![A=3[4^2]=48\ cm^2](https://tex.z-dn.net/?f=A%3D3%5B4%5E2%5D%3D48%5C%20cm%5E2)
Part 2) Find the perimeter of the figure
we know that
The perimeter of the figure is equal to two times the length side of the square, plus the circumference of six semicircles ( or the circumference of three circles)
Remember that
The circumference of a circle is equal to
where
D is the diameter of the circle
In this problem
so
![P=2(4)+3[\pi(4)]=(8+12\pi)\ cm](https://tex.z-dn.net/?f=P%3D2%284%29%2B3%5B%5Cpi%284%29%5D%3D%288%2B12%5Cpi%29%5C%20cm)
simplify
$19.4
Step-by-step explanation:
Simple Interest=SI
Principle(deposit)=P(97)
Rate= R(4/100=0.04)
Time= T(5)
SI=P•R•T
SI=97x0.04x5
SI=19.4
Interest earned = $19.4
Multiply both sides of the second equation by 100 to get rid of the decimals:
0.05<em>n</em> + 0.10<em>d</em> = 1.50
==> 5<em>n</em> + 10<em>d</em> = 150
Multiply both sides of the first equation by -5:
<em>n</em> + <em>d</em> = 21
==> -5<em>n</em> - 5<em>d</em> = -105
Add the two equations together:
(5<em>n</em> + 10<em>d</em>) + (-5<em>n</em> - 5<em>d</em>) = 150 + (-105)
Notice that the terms containing <em>n</em> get eliminated and we can solve for <em>d</em> :
(5<em>n</em> - 5<em>n</em>) + (10<em>d</em> - 5<em>d</em>) = 150 - 105
5<em>d</em> = 45
<em>d</em> = 45/5 = 9
Plug this into either original equation to solve for <em>n</em>. Doing this with the first equation is easiest:
<em>n</em> + 9 = 21
<em>n</em> = 21 - 9 = 12
So Donna used 12 nickels and 9 dimes.
We want double sixes. This means that we want both the first roll and the second roll to be 6.
The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll
Since we want both outputs to be 6, therefore, the answer would be: (6,6)
