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N76 [4]
2 years ago
9

Suppose a=3i-2j+k b=-i-4j+3k and c is avector lying along positive x axis with the property that a(b+c)=0 then find c?

Physics
1 answer:
il63 [147K]2 years ago
6 0

The value of the c will be (0 i+0 j+0 k). c is a vector that is along the positive x-axis and has the condition a(b+c)=0.

<h3>What is a vector?</h3>

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

Given ;

a=3i-2j+k

b=-i-4j+3k

Given property:

a(b+c)=0

-i-4j+3k ((-i-4j+3k)+c)=0

(3+8+3)(-i-4j+3k)c=0

14(-i-4j+3k)c=0

c=0 i+0 j+0 k

Hence, the value of the c will be (0 i+0 j+0 k).

To learn more about the vector refer to the link;

brainly.com/question/13322477

#SPJ1

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Answer:

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a)

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       F = - k * \Delta x (1)

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c)

  • When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.
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        \frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2}  = \frac{1}{2}*k*\Delta x^{2}   (5)

  • Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:

        \frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2}  = 4J   (6)

⇒      \frac{1}{2}* 200N/m* \Delta x_{1} ^{2}   = 4J  - 3.6 J = 0.4 J (7)

⇒     \Delta x_{1}   = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)

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