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3 years ago

Which chemical equation correctly shows the formation of water from hydrogen

Physics

2 answers:

nekit [7.7K]3 years ago

6 0

Answer:

d. H + O2 ------ H2O

that's the formation of water

IRISSAK [1]3 years ago

6 0

The correct answer is B.. then you will balance it.. after the balancing LHS hydrogen is 4, Oxygen is 2 then RHS hydrogen is 4 and Oxygen is 2.. it’s balanced . And the reactants and products are correct

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The United States and South Korean soccer teams are playing in the first round of the World Cup. An American kicks the ball, giv

Aleks04 [339]

Answer:v=2.82 m/s

Explanation:

Given

initial velocity of ball(u)=3.6 m/s

ball rolls a distance(s) of 5 m

ball acceleration $=-0.5 m/s^2$

Velocity of ball when it is intercepted by Korean player

$v^2-u^2=2as$

$v^2=3.6^2+2(-0.5)(5)=7.96$

$v=\sqrt{7.96}$

$v=2.82 m/s$

3 0

3 years ago

A hair dryer uses 1100 W of power

weqwewe [10]

Answer:10

Explanation:acellus

5 0

3 years ago

Read 2 more answers

A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm ons tionless bearings. Two 500 g blocks fall from above, hit the tum ble s

Verdich [7]

There are mistakes in the question.The correct question is here

A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. What is the turntable’s angular velocity, in rpm, just after this event?

Answer:

w=50 rpm

Explanation:

Given data

The mass turntable M=2kg

Diameter of the turntable d=20 cm=0.2 m

Angular velocity ω=100 rpm= 100×(2π/60) =10.47 rad/s

Two blocks Mass m=500 g=0.5 kg

To find

Turntable angular velocity

Solution

We can find the angular velocity of the turntable as follow

Lets consider turntable to be disk shape and the blocks to be small as compared to turntable

$I_{turntable}w=I_{block1}w^{i}+I_{turntable}w^{i}+I_{block2}w^{i}$

where I is moment of inertia

$w^{i}=\frac{I_{turntable}w}{I_{block1}w^{i}+I_{block2}w^{i}+I_{turntable}w^{i}}\\ So\\I_{turntable}=M\frac{r^{2} }{2}\\I_{turntable}=2*(\frac{(0.2/2)}{2} )\\ I_{turntable}=0.01 \\And\\I_{block1}=I_{block2}=mr^{2}\\I_{block1}=I_{block2}=(0.5)*(0.2/2)^{2} \\ I_{block1}=I_{block2}==0.005\\so\\w^{i}=\frac{I_{turntable}w}{I_{block1}w^{i}+I_{block2}w^{i}+I_{turntable}w^{i}}\\w^{i}=\frac{0.01*(10.47)}{0.005+0.005+0.01} \\w^{i}=5.235 rad/s\\w^{i}=5.235*(60/2\pi )\\w^{i}=50 rpm$

7 0

3 years ago

The turning radius of a car is 36ft. What will be the distance in meters?

ioda

(36 feet) x (1 meter / 3.28084 feet) = 10.973 meters (rounded)

7 0

4 years ago

1 mole of air undergoes a Carnot cycle. The hot reservoir is at 800 oC and the cold reservoir is at 25 oC. The pressure ranges b

BabaBlast [244]

Answer:

The net work produced is 30.37 KJ

The efficiency of cycle is 72.3%

Explanation:

For the net work produced, we have the formula:

Work = (Th - Tc)(Sh - Sc)(M)

Where,

Th = higher temperature = 800° C + 273 = 1073 k

Tc = lower temperature = 25° C + 273 = 298 k

Sh = specific entropy at higher temperature

Sc = specific entropy at lower temperature

M = molar mass of air

Using, ideal gas table to find entropy. The table is attached.

therefore,

Work = (1073 k - 298 k)(3.0485235 KJ/kg.k - 1.69528 KJ/kg.k)(0.02896 kg)

Work = (775 k)(1.3532435 KJ/kg.k)(0.02896 kg)

Now, for the efficiency (n), we have a formula:

n = 1 - Tc/Th

n = 1 - (298 k)/(1073 k)

5 0

4 years ago