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bija089 [108]
3 years ago
12

]Which of the following best describes the changes involved in a fission reaction?

Chemistry
1 answer:
zlopas [31]3 years ago
6 0
The nuclei of two small atoms combine to form one larger nucleus, releasing a large amount of energy. 
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When a plant responds to changes in the length of day by flowering during certain seasons, it is called
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Answer: photoperiodism

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Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of
Oksanka [162]

Answer:

B: increase.

Explanation:

When we are considering two gases A and B in a container at room temperature .

We have to find the change on  rate of reaction when the number of molecules of gases A is doubled

Let [A]=a and [B]=b

A+B\rightarrow product

Rate of reaction

R_1=k[A][B]=kab

We know that concentration is increases with increase in number of moles

When the number of molecules of gases A is doubled then concentration of gases A increases.

Therefore ,[A]=2a

Rate of reaction

R_2=k(2a)(b)=2kab

R_2=2R_1

Hence, the rate of reaction is  2 times the initial rate of reaction.Therefore, the rate of reaction will increase when the number of molecules of gases A is doubled.

Answer: B: increase.

4 0
3 years ago
Where is the Oort cloud located​
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7.Calculate the volume of nitrogen that reacts with 12dm3 of hydrogen with the volume of both gases measured at rtp:
marta [7]

Answer:

4.03dm³

Explanation:

The reaction expression is given as:

       3H₂   +   N₂   →    2NH₃  

  Volume of hydrogen  = 12dm³  

AT rtp:

             1 mole of gas occupies volume of 22.4dm³  

             x mole of hydrogen will occupy a volume of 12dm³

     Number of moles of hydrogen  = \frac{12}{22.4}   = 0.54mole

From the balanced reaction equation:

            3 mole of hydrogen gas combines with 1 mole of Nitrogen gas

         0.54 mole of hydrogen as will therefore combine with \frac{0.54}{3}   = 0.18moles of nitrogen gas

Since ;

                     1 mole of gas occupies a volume of 22.4dm³

               0.18moles of Nitrogen gas will occupy 0.18 x 22.4  = 4.03dm³

6 0
3 years ago
Write three primary alcohol with the formula C4H8O​
pishuonlain [190]

Answer:

CH2 will be CH-CH2-CH2OH

CH3-CH will beCH-CH2OH

CH2 will be C(CH3)-CH2OH

3 0
3 years ago
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