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bija089 [108]
2 years ago
12

]Which of the following best describes the changes involved in a fission reaction?

Chemistry
1 answer:
zlopas [31]2 years ago
6 0
The nuclei of two small atoms combine to form one larger nucleus, releasing a large amount of energy. 
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What is the electron configuration of the element in group 14 and period 4 of the periodic table
AlekseyPX

Answer: The first three elements i.e., C, Si & Ge form mostly the covalent compounds.

...

SALIENT FEATURES OF GROUP 14 (CARBON FAMILY) ELEMENTS.

Period 4

Element Germanium

Symbol Ge

Atomic number (Z) 32

Electronic configuration [Ar] 3d10 4s2 4p2

Explanation:

7 0
2 years ago
Melissa uses a sunscreen with an spf rating of 20. what does this does this mean?
Olin [163]
If the SPF rating is 20 then it means it would provide 20 times the protection instead of no sunscreen and 20 times longer someone would take before the person started to burn or in this case 200 minutes. 
4 0
3 years ago
Iron corrodes because _____ turns iron into ions through the process of _____. water, reduction
Setler [38]
Iron corrodes because <u>water</u> turns iron into ions through the process of <u>oxidation</u> 

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2 years ago
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6 0
2 years ago
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3 H2 (g) + N2 (g) 2 NH3 (g)
ale4655 [162]

Answer:

Mass = 0.697 g

Explanation:

Given data:

Volume of hydrogen = 1.36 L

Mass of ammonia produced = ?

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

3H₂ + N₂       →      2NH₃

First of all we will calculate the number of moles of hydrogen:

PV  = nRT

R = general gas constant = 0.0821 atm.L/mol.K

1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K

1.36 atm.L = n × 22.43 atm.L/mol

n = 1.36 atm.L / 22.43 atm.L/mol

n = 0.061 mol

Now we will compare the moles of hydrogen and ammonia:

                 H₂         :          NH₃

                  3          :            2

                0.061     :         2/3×0.061 = 0.041

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.041 mol × 17 g/mol

Mass = 0.697 g

4 0
3 years ago
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