One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.
The motion of atoms decrease when there is a decrease in velocity and kinetic energy that is decrease in temperature. this occurs during freezing and condensation.
Answer:
The answer to your questions are given below
Explanation:
The answer to the questions given above can simply be obtained by writing the electronic configuration of each atom.
The electronic configuration of each atoms can be written as follow:
Fluorine, F (9) => 1s² 2s²2p⁵
Sodium, Na (11) => [Ne] 3s¹
Helium, He (2) => 1s²
Calcium, Ca (20) => [Ar] s²
Nitrogen, N (7) => 1s² 2s²2p³
Sulphur, S (16) => [Ne] 3s²3p⁴
Answer:
I hope this helps 52.2 g/mol
Explanation:
1) Solve for the moles using PV = nRT:
n = PV / RT
n = [(700.0 mmHg / 760.0 mmHg atm¯1) (48.0 L)] / [(0.08206 L atm mol¯1 K¯1) (293.0 K)]
n = 1.8388 mol
2) Divide the grams given (96.0) by the moles just calculated above:
96.0 g / 1.8388 mol = 52.2 g/mol
