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BARSIC [14]
3 years ago
8

When 412.5 g of calcium carbonate react with 521.9 g of aluminum fluoride, how many

Chemistry
1 answer:
LekaFEV [45]3 years ago
5 0
Answer
321.8 g CaF2
321.5 g Al2(CO3)3
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There are three bulbs powered by a battery. What will happen if the middle light burns out.
Vadim26 [7]

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nuclear war ;P

Explanation:

8 0
2 years ago
Suppose you have a spherical balloon filled with air at room temperature and 1.0 atm pressure; its radius is 17 cm. You take the
Sladkaya [172]
<span>Answer: 17.8 cm
</span>

<span>Explanation:
</span>

<span>1) Since temperature is constant, you use Boyle's law:
</span>

<span>PV = constant => P₁V₁ = P₂V₂


</span><span>=> V₁/V₂ = P₂/P₁</span>
<span>
2) Since the ballon is spherical:


</span><span>V = (4/3)π(r)³</span>
<span>
Therefore, V₁/V₂ = (r₁)³ / (r₂)³
</span>

<span>3) Replacing in the equation V₁/V₂ = P₂/P₁:


</span><span><span>(r₁)³ / (r₂)³ </span>= P₂/P₁</span>
<span>
And you can solve for r₂: (r₂)³ = (P₁/P₂) x (r₁)³


</span>(r₂)³ = (1.0 atm / 0.87 atm) x (17 cm)³ = 5,647.13 cm³
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r₂ = 17.8 cm</span>

4 0
3 years ago
Read 2 more answers
How many grams of solid Ca(OH)2 (74.1 g/mol) are required to make 500 ml of a 3 M solution?
mars1129 [50]

Answer:

111.15 g are required to prepare 500 ml of a 3 M solution

Explanation:

In a 3 M solution of Ca(OH)₂ there are 3 moles of Ca(OH)₂ per liter solution. In 500 ml of this solution, there will be (3 mol/2) 1.5 mol Ca(OH)₂.

Since 1 mol of Ca(OH)₂ has a mass of 74.1 g, 1.5 mol will have a mass of

(1.5 mol Ca(OH)₂ *(74.1 g / 1 mol)) 111.15 g. This mass of Ca(OH)₂ is required to prepare the 500 ml 3 M solution.

3 0
2 years ago
Please help me, I really need it, God Bless you &lt;3
gladu [14]

#1

\\ \sf\longmapsto {}^{88}_{38}Sr^{2+}

  • As 2 electrons are donated Hence the No of electrons =38-2=36

#2

\\ \sf\longmapsto {}^{51}_{23}V^{3+}

  • As 3 electrons donated the no of electrons=23-3=20

#3

\\ \sf\longmapsto {}^{55}_{26}Fe^{3+}

  • No of neutrons=55-26=29

#4

\\ \sf\longmapsto {}^{112}_{48}

  • As 2 electrons are donated no of electrons =48-2=46

#5

\\ \sf\longmapsto {}^{210}_{82}Pb^{2+}

  • No of neutrons=210-82=128
7 0
2 years ago
Please help *chemistry*
Daniel [21]
3 because I just did it
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3 years ago
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