When 412.5 g of calcium carbonate react with 521.9 g of aluminum fluoride, how many
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The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
<h3>Position of 18o-labeled methanol in the products</h3>
The 18O label will appear at position b in the product as indicated in the image.
This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).
While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.
Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
Learn more about methanol here: brainly.com/question/17048792
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