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2 years ago

In the reaction mg 2hcl right arrow. mgcl2 h2 which element’s oxidation number does not change? cl mg h

Chemistry

1 answer:

netineya [11]2 years ago

5 0

The correct answer is Cl.

Chlorine is a substance that's employed in industry and is present in a number of household goods. There are times when chlorine takes the form of toxic gas. Chlorine gas can be converted into a liquid by applying pressure and cooling so that it can be transported and stored. The term "oxidation number" refers to the number of electrons that an element's atom either loses or gains during the production of a compound. The charge that an atom seems to have when forming ionic connections with other heteroatoms is used to define an atom's oxidation number. Even if it develops a covalent bond, an atom with a higher electronegativity is given a negative oxidation state.

Learn more about oxidation numbers here:-

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Which of the following describes a solution of 1 gram of salt dissolved in 500 mL of water?

Greeley [361]

Answer:

Explanation:

Homogeneous= all particles are dissolved thoroughly

Solute= 1 gram of salt

Solvent= 500 mL water

8 0

3 years ago

Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu

oksano4ka [1.4K]

Answer:

5000 and $8\times 10^{7}$ indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: $K=\frac{[B]}{[A]}$

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

So, $K=\frac{[B]}{[A]}>1$

As, both 5000 and $8\times 10^{7}$ are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium

4 0

3 years ago

Jordan wonders why there is dew on the grass in the morning. He asks a few friends to see what they think. His friend Tasha says

kykrilka [37]

No because dew is water droplets that come from condensation rather than from rain coming at night

4 0

3 years ago

Read 2 more answers

Nail polish remover containing acetone was spilled in a room 7.2 m × 5.8 m × 3.9 m. Measurements indicated that 6,400 mg of acet

sergeinik [125]

Volume of room = $7.2 m \times 5.8 m \times 3.9 m$

= $162.864 m^{3}$

Now, according to conversion factor, convert 6,400 mg to micrograms

Since, 1 mg is equal to 1000 microgram.

Therefore, 6,400 mg = $6,400 \times 1000$

= 6,400,000 micrograms of acetone.

To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.

Thus,

Concentration of acetone = $\frac{6,400,000 microgram}{162.864 m^{3}}$

= 39296.5910 microgram per cubic meter or $3.92\times 10^{4} \mu g/m^{3}\simeq 4.0\times 10^{4} \mu g/m^{3}$

Hence, concentration of acetone is equal to $4.0\times 10^{4} \mu g/m^{3}$

7 0

3 years ago

Fill in the coefficients that was will balance the following reaction SnSO4 + KBr SnBr2 K2SO4

Juliette [100K]

The coefficients are 1 : 2 : 1 : 1

<u>Explanation:</u>

To be a balanced equation, the chemical equation should have has equal number of atoms on both reactant and product side.

Given chemical equation:

$a_{0} {SnSO}_{4}+a_{1} K B r \rightarrow a_{2} {SnBr}_{2}+a_{3} K_{2} S O_{4}$

Now, calculate the number of atoms present in reactant side:

Sn - 1

$S O_{4}$ - 1

K - 1

Br - 1

Then, calculate the number of atoms present in product side:

Sn - 1

$S O_{4}$ - 1

K - 2

Br - 2

Therefore, in order to balance this given chemical equation multiply KBr by 2 on reactant side. So, the balanced chemical equation is as follows.

$\Sn S O_{4}+2 K B r \rightarrow S n B r_{2}+K_{2} S O_{4}$

Hence,

$a_{0} - 1\\a_{1} - 2\\a_{2} - 1\\a_{3} - 1$

8 0

3 years ago