Answer:
The answer to your question is: 0.118 moles of water
Explanation:
Data
moles of water = ?
Vol of O2= 1.6
Temp = 324°K
Pressure = 0.984 atm
R = 0.082 atm l / mol°K
Process
1.- Calculate the moles of O₂ using the ideal gas formula.
PV = nRT
![n = \frac{PV}{RT}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7BPV%7D%7BRT%7D)
![n = \frac{(1.6)(0.984)}{(0.082)(324)}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B%281.6%29%280.984%29%7D%7B%280.082%29%28324%29%7D)
![n = \frac{1.5744}{26.568}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B1.5744%7D%7B26.568%7D)
n = 0.059 moles of oxygen
2.- Find the moles of water
2 moles of water ------------------ 1 mol of oxygen
x ------------------ 0.059 moles
x = (0.059 x 2) / 1
x = 0.118 moles of water
Answer:
T₂ = 51826.1 K
Explanation:
Given data:
Initial Volume = 2.3 L
Final volume = 400 L
Initial temperature = 25 °C (25+ 273 = 298 K)
Final temperature = ?
Solution:
V₁/T₁ = V₂/T₂
T₂ = V₂ T₁/V₁
T₂ = 400 L . 298 K / 2.3 L
T₂ = 119200 K. L / 2.3 L
T₂ = 51826.1 K
<span>D. not enough precipitation is the answer</span>
The answer is D. i believe so.
Answer:
tend to form ionic bonds by losing electrons making these atoms positive charge.
Explanation: